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3 years ago

⚠️❗️⚠️❗️⚠️❗️25 POINTS PLEASE FIND THE AREA TROLLS WILL BE REPORTED⚠️⚠️❗️❗️⚠️❗️⚠️

Mathematics

1 answer:

Leya [2.2K]3 years ago

4 0

Answer:

you need a photo or the answer written down

Step-by-step explanation:

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Where is expression that equals 40 it through the exponent

Lisa [10]

10 it the power of 4

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3 years ago

In Mr. Harold's class there are 12 students. They each have 5 pencils. Some of the students, s, each lost 2 pencils. Now, the st

Katena32 [7]

The answer would be C. (12 x 5) - (s x 2) = 38.

This is because if there are 12 students with 5 pencils per student, we can say 12 x 5. Then, think of the phrase, two pencils lost per student. That would be 2s, or (s x 2). Since it’s lost, we would subtract that amount from 12 x 5.

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3 years ago

What is the inverse of g(x) = X +8

gayaneshka [121]

Answer:

The inverse is x-8

Step-by-step explanation:

g(x) = x+8

y = x+8

To find the inverse, exchange x and y

x = y+8

Solve for y

Subtract 8 from each side

x-8 = y+8-8

x-8 = y

The inverse is x-8

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3 years ago

Will give brainlest :)

snow_lady [41]

Answer:

Step-by-step explanation:

4 0

3 years ago

The managers of 21 supermarkets counted the number of cars in their parking lots on the same day. The results are shown in the l

mixer [17]

The IQR is 42.5

Step-by-step explanation:

Interquartile range is the difference of third and first quartile.

First of all we have to find the median for that purpose the data has to be arranged in ascending order. The data is already in ascending order.

As the number of values are odd

n=21

The median will be: $(\frac{n+1}{2}) th\ term$

Putting n=21

$(\frac{21+1}{2})th\ term\\=(\frac{22}{2})th\ term\\= 11th\ term$

The 11th term is 133

So median = 133

Now the data is divided into two halves

One is: 98, 100, 101, 102, 108, 109, 111,118, 129, 132

2nd is: 135, 135, 145, 146, 146, 156, 170 176, 180, 180

Q1 will be the median of first half and Q3 will be the median of 2nd half.

As now the halves contain even number of values, the medians will be the average of middle two values

For First Half:

98, 100, 101, 102, 108, 109, 111,118, 129, 132

$Q_1 = \frac{108+109}{2}\\Q_1 = \frac{217}{2}\\Q_1 = 108.5$

For Second Half:

135, 135, 145, 146, 146, 156, 170 176, 180, 180

$Q_2 = \frac{146+156}{2}\\Q_2 = \frac{302}{2}\\Q_2 = 151$

Now

Interquartile Range:

$IQR = Q_3-Q_1\\= 151-108.5\\=42.5$

Hence,

The IQR is 42.5

Keywords: Median, IQR

Learn more about median at:

#LearnwithBrianly

7 0

3 years ago