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3 years ago

Please help me i beg of u also due today

Mathematics

1 answer:

lara31 [8.8K]3 years ago

5 0

Answer:

35) A. 21.2

46) D. 4/7

30) B. 4.4

42) C. Prism

Step-by-step explanation:

35) see first two attached files. 134.3 - 113.1 = 21.2

46) see third attached file. 4/7 = .5714ish and 112 pi = 351.59 ish

30) see fourth attached file.

42) prisms are in no way circular so it cant have a circular base when cut

ok hope this helps!! <3

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SOMEONE HELP ASAPPPP PLEASEEE,PLEASE EXPLAIN HOW U GOT YOUR ANSWER, I NEED AN EXPLANATION IN ORDER TO COMPLETE THIS! NO LINKS OR

kaheart [24]

Answer:

x = 5

Step-by-step explanation:

4x + 2y + z = 24

2x - 3y - z = 2

5x + y + 2z = 21

-----------------

Eliminate z

Add the 1st and 2nd eqn

4x + 2y + z = 24

2x - 3y - z = 2

----------------

6x - 1y = 26 eqn A

Multiply the 2nd eqn by 2, then add the 3rd.

4x - 6y -2z = 4

5x + y + 2z = 21

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9x - 5y = 25 eqn B

---------------

Now you have 2 eqns in 2 unknowns, not 3.

Multiply eqn A by 5 and subtract eqn B.

30x - 5y = 130 eqn A times 5

9x - 5y = 25 eqn B

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21x = 105

x = 5

4 0

3 years ago

Read 2 more answers

Determine if triangle ABC with coordinates A (0, 2), B (2, 5), and C (−1, 7) is an isosceles triangle. Use evidence to support y

kirill115 [55]

Answer:

The triangle ABC is an isosceles right triangle

Step-by-step explanation:

we have

The coordinates of triangle ABC are

A (0, 2), B (2, 5), and C (−1, 7)

we know that

An isosceles triangle has two equal sides and two equal internal angles

The formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

step 1

Find the distance AB

substitute in the formula

$d=\sqrt{(5-2)^{2}+(2-0)^{2}}$

$d=\sqrt{(3)^{2}+(2)^{2}}$

$dAB=\sqrt{13}\ units$

step 2

Find the distance BC

substitute in the formula

$d=\sqrt{(7-5)^{2}+(-1-2)^{2}}$

$d=\sqrt{(2)^{2}+(-3)^{2}}$

$dBC=\sqrt{13}\ units$

step 3

Find the distance AC

substitute in the formula

$d=\sqrt{(7-2)^{2}+(-1-0)^{2}}$

$d=\sqrt{(5)^{2}+(-1)^{2}}$

$dAC=\sqrt{26}\ units$

step 4

Compare the length sides

$dAB=\sqrt{13}\ units$

$dBC=\sqrt{13}\ units$

$dAC=\sqrt{26}\ units$

$dAB=dBC$

therefore

Is an isosceles triangle

Applying the Pythagoras Theorem

$(AC)^{2} =(AB)^{2}+(BC)^{2}$

substitute

$(\sqrt{26})^{2} =(\sqrt{13})^{2}+(\sqrt{13})^{2}$

$26=13+13$

$26=26$ -----> is true

therefore

Is an isosceles right triangle

8 0

3 years ago

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kumpel [21]

Answer:

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Step-by-step explanation:

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3 years ago

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The function g is defined by g(x)= 3x2 - 3.<br> Find g(3z).

vagabundo [1.1K]

=3(3z)2-3
=3(9z2)-3
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5 0

3 years ago

Atul has 2/3 lb of candy. Jose has 3/5 lb and Maria has 1/2 lb less then José. How many more pounds of candy does Atul have than

liraira [26]

Given:

Atul has $\dfrac{2}{3}$ lb of candy.

Jose has $\dfrac{3}{5}$ lb of candy.

Maria has $\dfrac{1}{2}$ lb less than Jose.

To find:

How many more pounds of candy does Atul have than Maria?

Solution:

Since, Maria has $\dfrac{1}{2}$ lb less than Jose, therefore

Maria has = $\dfrac{3}{5}-\dfrac{1}{2}$ lb

Maria has = $\dfrac{6-5}{10}$ lb

Maria has = $\dfrac{1}{10}$ lb

Difference between the candies Atul and Maria have.

Difference = $\dfrac{2}{3}-\dfrac{1}{10}$ lb

Difference = $\dfrac{20-3}{30}$ lb

Difference = $\dfrac{17}{30}$ lb

Therefore, Atul have $\dfrac{17}{30}$ lb of candy more than Maria.

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3 years ago