Let x be the number of 52 cent stamps that Sally has and let y be the number of 34 cent stamps that she has.
Then,
52x + 34y = 1150 --- (1)
Also, she has six more 34 cent stamps than 52 cent stamps.
Therefore, y = x + 6
(1) becomes
52x + 34(x + 6) = 1150
52x + 34x + 204 = 1150
86x + 204 = 1150
86x = 1150 - 204
86x = 946
x = 11
and y = 11 + 6 = 17
Hence, Sally has eleven 52 cent stamps and seventeen 34 cent stamps.
Answer:
x = 30 and y = -34
Step-by-step explanation:
Given the following functions
(1/4)^(x+y) = 256... 1
log₄(x-y) = 3.... 2
From equation 2;
x-y = 4³
x-y = 64
x = 64 + y ... 3
Substitutw 3 into 1
From 1:
(1/4)^(x+y) = 256
(1/4)^(64+y+y) = 256
(1/4)^(64+2y) = 256
Take log₄ of both sides
64+2y log₄ (1/4) = log₄256
-(64+2y) = 4log₄4
-(64+2y) = 4
64+2y = -4
2y = -4 - 64
2y = -68
y = -34
Since
x = 64 + y .
x = 64 - 34
x = 30
Hence x = 30 and y = -34
Answer:
-10; no
Step-by-step explanation:
<h2>
-4*3 + 9*2 + 8*-2 = -10</h2><h2>
</h2><h2>
-10 does not equal 0 so it is not perpendicular</h2>
5^2 + x^2=8^2
25+x^2=64
X=6.2
