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3 years ago

Pls answer quick I will give brainliest

Mathematics

1 answer:

eimsori [14]3 years ago

6 0

Answer:

EBC and CBF are supplementary.

EBD=66

Step-by-step explanation:

Since vertical angles are congruent, ABE=CBF

ABE=40-x

40-x + 6x-30=90

5x+10=90

5x=80

x=16

16(6)-30=66

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Solve sin 0 + 1 = cos20 on the interval 0 ≤ 0 < 2pi. Show work please!

yan [13]

Answer:

$\theta=\frac{\pi}{2},\frac{3\pi}{2}\frac{2\pi}{3}\frac{4\pi}{3}$

Step-by-step explanation:

You need 2 things in order to solve this equation: a trig identity sheet and a unit circle.

You will find when you look on your trig identity sheet that

$cos(2\theta)=1-2sin^2(\theta)$

so we will make that replacement, getting everything in terms of sin:

$sin(\theta)+1=1-2sin^2(\theta)$

Now we will get everything on one side of the equals sign, set it equal to 0, and solve it:

$2sin^2(\theta)+sin(\theta)=0$

We can factor out the sin(theta), since it's common in both terms:

$sin(\theta)(2sin(\theta)+1)=0$

Because of the Zero Product Property, either

$sin(\theta)=0$ or

$2sin(\theta)+1=0$

Look at the unit circle and find which values of theta have a sin ratio of 0 in the interval from 0 to 2pi. They are:

$\theta=\frac{\pi}{2},\frac{3\pi}{2}$

The next equation needs to first be solved for sin(theta):

$2sin(\theta)+1=0$ so

$2sin(\theta)=-1$ and

$sin(\theta)=-\frac{1}{2}$

Go back to your unit circle and find the values of theta where the sin is -1/2 in the interval. They are:

$\theta=\frac{2\pi}{3},\frac{4\pi}{3}$

7 0

3 years ago

Please help me on this it’s due

olya-2409 [2.1K]

<h3>Answer: 5 cakes</h3>

================================================

Explanation:

Let's start off converting the mixed number 12 & 1/4 to an improper fraction.

$a \frac{b}{c} = \frac{a*c+b}{c}\\\\12 \frac{1}{4} = \frac{12*4+1}{4}\\\\12 \frac{1}{4} = \frac{49}{4}\\\\$

Do the same for the other mixed number 2 & 1/3.

$a \frac{b}{c} = \frac{a*c+b}{c}\\\\2 \frac{1}{3} = \frac{2*3+1}{3}\\\\2 \frac{1}{3} = \frac{7}{3}\\\\$

-----------------------

From here, we divide the two fractions. I converted them to improper fractions to make the division process easier.

$\frac{49}{4} \div \frac{7}{3} = \frac{49}{4} \times \frac{3}{7}\\\\\frac{49}{4} \div \frac{7}{3} = \frac{49\times 3}{4\times 7}\\\\\frac{49}{4} \div \frac{7}{3} = \frac{7\times 7\times 3}{4\times 7}\\\\\frac{49}{4} \div \frac{7}{3} = \frac{7\times 3}{4}\\\\\frac{49}{4} \div \frac{7}{3} = \frac{21}{4}\\\\$

The last step is to convert that result to a mixed number.

$\frac{21}{4} = \frac{4*5+1}{4}\\\\\frac{21}{4} = \frac{4*5}{4}+\frac{1}{4}\\\\\frac{21}{4} = 4+\frac{1}{4}\\\\\frac{21}{4} = 5 \frac{1}{4}\\\\$

Note that 21/4 = 5.25 and 1/4 = 0.25 to help check the answer.

-----------------------

Therefore, she can make 5 cakes. The fractional portion 1/4 is ignored since we're only considering whole cakes rather than partial ones.

3 0

3 years ago

In the same circle or in congruent circles:

Natali5045456 [20]

Answer:

congruent minor

Step-by-step explanation:

two congruent circle are corresponding minor

8 0

3 years ago

HELLELELELLELELEP!!!

Eva8 [605]

Answer:

f = -15

Step-by-step explanation:

7 0

3 years ago

Cuál es el perímetro del triángulo amarillo?

Maslowich

Answer:

a/2 + b unidades

Step-by-step explanation:

Mi primera lengua es ingles (tienes paciencia por favor). Se da que la parte inferior es a/2 unidades. La parte anaranjada tiene un lado que es b/2, entonces todos los lados son b/2 tambien. Entonces el lado del derecho es b/2. La izquierda es b/2 tambien ( se da eso). Entonces el perimetro del triangulo amarillo es a/2 + b/2 + b/2 = a/2 + b unidades.

5 0

3 years ago