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JulsSmile [24]
3 years ago
8

Given g(x) = x square -7x + 1over4 show that the least possible value of g(x) is -12

Mathematics
1 answer:
aliina [53]3 years ago
5 0

Answer:

-\frac{45}{16}

Step-by-step explanation:

g(x)=\frac{x^{2} -7x+1}{4}

Take the derivate of g:

g'(x)=\frac{x-7}{4}

Find x that:

g'(x)=0

<h2>solving:</h2>

\frac{2x-7}{4}=0\\x=\frac{7}{2}

This x give the least possible value that are g(7/2):

g(\frac{7}{2}) =-\frac{45}{16}

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