Question

Given g(x) = x square -7x + 1over4 show that the least possible value of g(x) is -12

Answer 1

Answer:

$-\frac{45}{16}$

Step-by-step explanation:

$g(x)=\frac{x^{2} -7x+1}{4}$

Take the derivate of g:

$g'(x)=\frac{x-7}{4}$

Find x that:

g'(x)=0

solving:

$\frac{2x-7}{4}=0\\x=\frac{7}{2}$

This x give the least possible value that are g(7/2):

$g(\frac{7}{2}) =-\frac{45}{16}$