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3 years ago

Given g(x) = x square -7x + 1over4 show that the least possible value of g(x) is -12

Mathematics

1 answer:

aliina [53]3 years ago

5 0

Answer:

$-\frac{45}{16}$

Step-by-step explanation:

$g(x)=\frac{x^{2} -7x+1}{4}$

Take the derivate of g:

$g'(x)=\frac{x-7}{4}$

Find x that:

g'(x)=0

<h2>solving:</h2>

$\frac{2x-7}{4}=0\\x=\frac{7}{2}$

This x give the least possible value that are g(7/2):

$g(\frac{7}{2}) =-\frac{45}{16}$

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3 years ago

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elena55 [62]

Answer:

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Step-by-step explanation:

We are in posession of the sample's standard deviation, so we use the student's t-distribution to find the confidence interval.

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99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 35 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.99}{2} = 0.905([tex]t_{995}$ ). So we have T = 2.9467

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3 years ago