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evablogger [386]
1 year ago
15

Bob Ross bought a Blackberry on the Web for $90.49. He saw the same Blackberry in the mall for $120.21. How much did Bob save by

buying on the Web?
Note: Round your answer to the nearest cent.
Mathematics
1 answer:
liraira [26]1 year ago
5 0

Answer:

$29.72

Step-by-step explanation:

$120.21-$90.49=$29.72

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Apr 22, 12:47:51PM
trapecia [35]
Your straight line is east-west
7 0
3 years ago
A number when divided by 780 gives remainder 38 .What
baherus [9]

Given:

A number when divided by 780 gives remainder 38.

To find:

The reminder that would be obtained by dividing same number by 26.

Solution:

According to Euclis' division algorithm,

a=bq+r                ...(i)

Where, q is quotient and 0\leq r is the remainder.

It is given that a number when divided by 780 gives remainder 38.

Substituting b=780,\ r=38 in (i), we get

a=(780)q+38

So, given number is in the form of 780q+38, where q is an integer.

On dividing 780q+38 by 26, we get

\dfrac{780q+38}{26}=\dfrac{780q}{26}+\dfrac{38}{26}

\dfrac{780q+38}{26}=30q+\dfrac{26+12}{26}

\dfrac{780q+38}{26}=30q+\dfrac{26}{26}+\dfrac{12}{26}

\dfrac{780q+38}{26}=30q+1+\dfrac{12}{26}

Since q is an integer, therefore (30q+1) is also an integer but \dfrac{12}{26} is not an integer. Here 26 is divisor and 12 is remainder.

Therefore, the required remainder is 12.

4 0
3 years ago
Pleaseee helpppp:)))
matrenka [14]

Answer:

<h2><em><u>Option</u></em><em><u> </u></em><em><u>B</u></em><em><u>:</u></em></h2><h3><em><u>112</u></em><em><u> </u></em><em><u>families</u></em><em><u> </u></em></h3>

Step-by-step explanation:

<em><u>Given</u></em><em><u>,</u></em>

No. of families = 75

Out of 75 no. of families had cars = 42

Out of 1, no. of families can have cars

=  \frac{42}{75}

<em><u>Therefore</u></em><em><u>, </u></em>

Out of 200 families, no. of families had cars

= 200 \times  \frac{42}{75}

=200 \times   \frac{14}{25}

= 8 × 14

= 112

<em><u>Hence</u></em><em><u>, </u></em>

<em><u>option</u></em><em><u> </u></em><em><u>B</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>correct</u></em><em><u> </u></em><em><u>as</u></em><em><u> </u></em><em><u>112</u></em><em><u> </u></em><em><u>families</u></em><em><u> </u></em><em><u>have</u></em><em><u> </u></em><em><u>cars</u></em><em><u> </u></em><em><u>out</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>200</u></em><em><u> </u></em><em><u>families</u></em><em><u> </u></em><em><u>(</u></em><em><u>Ans</u></em><em><u>)</u></em>

5 0
2 years ago
Rhonda has $13. She has one $5 bill, three $1 bills, and one other bill. Is a other bill a $1 bill or a $5 bill explain
morpeh [17]

Answer:

$5 bill

Step-by-step explanation:

If Rhonda has $13 and she has a $5 bill and 3 $1 bills, then she has

5 + 3(1) + x = 13

5 + 3 + x = 13

8 + x = 13

x = 5.

The last bill must be a $5 bill to equal the remaining $5.

8 0
2 years ago
How do I solve this?
Katena32 [7]
We’re the problem bro sorry can’t help you bud
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3 years ago
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