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3 years ago

Divide: 5a^6+60a^5-40a^4/20a^4

Mathematics

1 answer:

vlada-n [284]3 years ago

6 0

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Answer: a^2/4 + 3a - 2

I hope this helped!

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Identify the factors of the terms of the expression. 3). 5+6a+11b 4). 13m-2n

xeze [42]

Answer:

factors are 5, 6, a, 11, b

Step-by-step explanation:

3) 5 + 6a + 11b

Algebraic expressions: 5 + 6a + 11b 

Are combinations of numbers, variables, and at least one arithmetic.

Term are: 5, 6a, 11b

Each expression is made up of terms. A term can be a signed number, a variable, or a constant multiplied by a variable(s).

Factors are: 5, 6, a, 11, b

Something which is multiplied by something else. A factor can be a variable, number, a term, or a longer expression.

Coefficient: 6, 11

The numerical factor of a multiplication expression that contains a variable.

Constant: 5 

A number that cannot change its value.

4). 13m-2n (note: it applies as above)

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3 years ago

I don’t think i have the right answer so I’m checking it to make sure

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I believe the answer is the last one. I hope this helps love! :)

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3 years ago

Thirty-six of the students in the school choir like to sing solos. These 36 students make up 24% of the choir. How many students

lubasha [3.4K]

Answer:

150

Step-by-step explanation:

We can write a proportion to find the total amount in the choir using the information given. A proportion is two equivalent ratios set equal to each other.

$\frac{24}{100}=\frac{36}{y}$

We will cross multiply the numerator of one ratio with denominator of the other. And then solve for y.

24y=100(36)

24y=3600

y=150.

There are 150 students in the choir.

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3 years ago

What is the solution to the inequality

Dvinal [7]

Answer:

p > 5 and p <-8

Step-by-step explanation:

To solve this, you first need to isolate p.

First add 6 on both sides of the equation:

$-6 + |2p+3| >7\\\\(+6) -6 + |2p+3| >7 +6\\\\2p + 3 > 13$

Then subtract 3 from both sides of the equation.

$2p+3-3>13-3\\\\2p > 10\\$

The divide both sides by 2.

$\dfrac{2p}{2}>\dfrac{10}{2}\\\\p>5$

Another solution is possible because of the absolute value.

If $|2p+3|>13$

Then $|2p+3|$

Thus we can solve the second solution:

$|2p+3|$

$2p+3$

Isolate P again by subtracting both sides by 3

$2p+3-3$

$2p$

Then divide both sides by 2:

$\dfrac{2p}{2}$

$p$

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