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3 years ago

In the fruit bowl the ratio of apples, bananas, and pears is 4.2, 5. If the total

Mathematics

1 answer:

Sergio039 [100]3 years ago

6 0

Answer:

5:11

Step-by-step explanation:

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<img src="https://tex.z-dn.net/?f=%5Csf%2023%289x%2B6%29%3D6x%2B4" id="TexFormula1" title="\sf 23(9x+6)=6x+4" alt="\sf 23(9x+6)=

ozzi

The value of x from the given expression is; x= -2/3

<h3>Solving one-variable equations</h3>

The given expression is;

23(9x+6) = 6x + 4.

Hence, when we expand the equation; we have;

207x + 138 = 6x +4

207x - 6x = 4 - 138

201x = -134

x = -134/201

x = -2/3

Read more on one-variable equations;

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4 0

2 years ago

Read 2 more answers

Find x if x-l/x-1=-1

shusha [124]

X= X^2 hope it helps :)

8 0

4 years ago

The temperature changed from 7°F at 6 p.M to -5°F at midnight. What was the difference between the high and low temperatures? Wh

IgorC [24]

Answer:

12 °F

2°F per hour

Step-by-step explanation:

The difference can be found by substracting:

7°F-( -5 °F)

=12 °F

To find the average change in temperature per hour, divide by how many hours between 6 to midnight. Between 6 to midnight is 6 hours.

12°F / 6 hours

= 2°F/ hour

7 0

3 years ago

Freddie invests £6600 in an account that pays 3 % compound interest per annum for the two years, then 1 % . Work out how much mo

algol [13]

Answer:

Step-by-step explanation:

3% of 6600 = 198

1% or 6600 = 66

6600 + 198 + 198 + 66 + 66 + 66 + 66 + 66 + 66 = 7392

5 0

3 years ago

A random sample of adults were asked whether they prefer reading an e-book over a printed book. The survey resulted in a sample

djyliett [7]

Answer: $(0.10\ ,\ 0.18)$

Step-by-step explanation:

According to the empirical rule, the 95% confidence interval for the true population proportion is given by :-

$(p'-2\sigma_{p'}\ ,\ p'+2\sigma_{p'})$

Given : . The survey resulted in a sample proportion of p′=0.14, with a sampling standard deviation of σp′=0.02, who preferred reading an e-book.

Then, the 95% confidence interval for the true proportion of adults who prefer e-books will be :-

$(0.14-2(0.02)\ ,\ 0.14+2(0.02))\\\\=(0.14-0.04\ ,\ 0.14+0.04)\\\\=(0.10\ ,\ 0.18)$

Hence, the 95% confidence interval for the true proportion of adults who prefer e-books= $(0.10\ ,\ 0.18)$

8 0

3 years ago