Answer:
The length of the field on the drawing is 55 cm.
Step-by-step explanation:
Given:
Mark made a scale drawing of a soccer field.
Using a scale of .5 cm=1 m.
The actual length of the field is 110 m.
Now, to find the length of the field on drawing.
Let the length of the field on drawing be 
As given 0.5 cm is equivalent to 1 m.
Thus, 
is equivalent to 110 m.
Now, to get the length of the field on drawing by using cross multiplication method:
<em>By cross multiplying we get:</em>
⇒ 
⇒ 
Therefore, the length of the field on the drawing is 55 cm.
Answer:
y- intercept --> Location on graph where input is zero
f(x) < 0 --> Intervals of the domain where the graph is below the x-axis
x- intercept --> Location on graph where output is zero
f(x) > 0 --> Intervals of the domain where the graph is above the x-axis
Step-by-step explanation:
Y-intercept: The y-intercept is equivalent to the point where x= 0. 'x' is the input variable in an equation, therefore the y-intercept is where the input, or x, is equal to 0.
f(x) <0: Notice the 'lesser than' sign. This means that the value of f(x), or 'y', is less than 0. This means that this area consists of intervals of the domain below the x-axis.
X-intercept: The x-intercept is the location of the graph where y= 0, or the output is equal to 0.
f(x) >0: In this, there is a 'greater than' sign. This means that f(x), or 'y', is greater than 0. Therefore, this consists of intervals of the domain above the x-axis.
Answer:
80 / 60 = 1.3 approximately
Step-by-step explanation:
The answer is c I might be wrong
Answer:
Growth rate = ln(1.1)/2
Step-by-step explanation:
Given:
P1 = 1.1 P0
Number of year n = 2
Computation:
P1 = P0[eⁿˣ]
x = growth rate
So,
1.1 P0 = P0[eⁿˣ]
1.1 = eⁿˣ
1.1 = e²ˣ
By taking log
Growth rate = ln(1.1)/2
