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AlladinOne [14]
3 years ago
12

Turn 25/4 into a mixed number

Mathematics
1 answer:
horsena [70]3 years ago
3 0
Mixed number is 6 1/4





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What is the length of the hypotenuse of a right triangle with sides that measure 7 cm and 24 cm?
Paul [167]

The length of the hypotenuse of a right triangle with sides that measure 7 cm and 24 cm is 25 cm

<u>Solution:</u>

Given a right angled triangle,

The sides measure 7 cm and 24 cm

We have to find the length of hypotenuse

For a right angled triangle, by Pythagorean theorem, which states that the square of the length of the hypotenuse is equal to the sum of squares of the lengths of other two sides of the right-angled triangle.

From above definition we get,

c^2 = a^2 + b^2

Where, "c" is the length of hypotenuse

"a" is the length of one side of triangle

"b" is the length of other side of triangle

Here, a = 7 and b = 24 and c = ?

c^2 = 7^2 + 24^2\\\\c^2 = 49 + 576 = 625

Taking square root on both sides,

c = \sqrt{625}\\\\c = 25

Hence the length of hypotenuse is 25 cm

7 0
3 years ago
What is the length of a diagonal D of a cube that is 10 inches on each edge?
algol [13]
(10^2 +10^2)^.5  = 10*(sqrt2)
4 0
3 years ago
Can someone answer part A and part B?
Marat540 [252]

Answer:

Part a: 3

Part b: B

Step-by-step explanation:

3*3=9*3=27

27/3=9

3 0
3 years ago
No biggy just need some help
Temka [501]

Answer:

betwen year 5 and 6

Step-by-step explanation:

th prize will drop betwen 5 and 6 years.

i think its the correct answer

8 0
3 years ago
Ship A and Ship B are 120 km apart when they pick up a distress call from another boat. Ship B estimates that they are 70 km awa
oksian1 [2.3K]

Answer:

147.5 km and 64.4 km

Step-by-step explanation:

a=120  km

b=70  km

β=28 degrees ( ∘)

 

b^2=(a^2)+(c^2)−2ac*cosβ  

70^2 =(120^2 )+(c^2)−2⋅ 120⋅ c⋅ cos(28∘ )  

 (c^2 ) −211.907c+9500=0  

 

note p, q, and r are replacement variables in the Pythagorean theorem since a, b, and c are already in use

p=1;q=−211.907;r=9500  

D=(q^2 ) −4pr=(211.907^2 )−4⋅1⋅9500=6904.75561996  

D>0  

 

c_{1,2}  =   (−q±  \sqrt{D}   )/2p=(211.91±\sqrt{6904.76})/2

​c_{1,2}  =105.95371114±41.5474295834  

(c_{1}−147.501140726)(c_{2}−64.4062815596)=0

c_{1}=147.501140726  

c_{2}=64.4062815596  

5 0
3 years ago
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