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AlladinOne [14]
3 years ago
12

Turn 25/4 into a mixed number

Mathematics
1 answer:
horsena [70]3 years ago
3 0
Mixed number is 6 1/4





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Help me people u r my only hope!
Y_Kistochka [10]

Answer:

D)1/3 ?

Step-by-step explanation:

Maybe 1/3

Do some research, I guess it's D).

I hope that helps (:

1. The entire fraction is negative if the numerator or denominator are negative.

if both parts of the fraction were negative, the entire fraction would be positive (- / - = +)

2. Of course, although most teachers ask you to put the negative sign in the fraction as a whole (before the fraction line) or in the numerator. never leave a fraction with two signs. in this case, if it has two signs and they are different, the whole fraction is NEGATIVE

3) No. the whole fraction is POSITIVE only if both the numerator and the denominator have the same sign, + + or - -

8 0
3 years ago
What is the value for X.
Kryger [21]

Answer:

It is 58 degrees

3 0
3 years ago
I’m confused on this one
Ghella [55]

In a parallelogram, the opposite angles will be congruent to each other.


In this parallelogram, angles B and C are congruent, and angles A and D are congruent.


We will work on angles B and C first. Set the two angles to equal each other:


12x + 6 = 6x + 66


Subtract 6 from both sides:


12x = 6x + 60


Subtract 6x from both sides:


6x = 60


Divide both sides by 6 to get x by itself:


\boxed{x = 10}


x will equal 10.


Set angles A and D to equal each other:


54 = 3y


Divide both sides by 3 to get y by itself:


\boxed{y = 18}


y will equal 18.


The x and y values that make this quadrilateral a parallelogram will be x = 10, and y = 18.

3 0
3 years ago
What equation is graphed in this figure?
bixtya [17]
The answer is C

Here is the process, hope it helps!
y+2=-3/2(x-2)
y+2=-3/2x+3
y=-3/2x+1

4 0
3 years ago
Given the ordered pair P(1, -3), determine the requested secant, cosecant, or cotangent of angle ?. Cot ? = _____
maxonik [38]

\bf P(\stackrel{x}{1},\stackrel{y}{-3})\qquad \qquad cot(\theta )=\cfrac{\stackrel{\stackrel{adjacent}{x}}{1}}{\stackrel{\stackrel{opposite}{y}}{-3}}

5 0
4 years ago
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