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3 years ago

A parabola has a vertex of (5,4) and goes through the point (6,-10)

1 answer:

5 0

Y = -2(x-5)^2 + 4

Note: vertex form is 0, f(x), y, or nothing= a(x-h)^2 + k
The opposite of the x value of the vertex is h
The y value value of the vertex is k.

Find a. Plug in (6,-10)

-10 = a(6-5)^2 + 4
-10 = 1a + 4
-10 = 5a
a = -2

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kykrilka [37]

The value of the cosine ratio cos(L) is 5/13

<h3>How to determine the cosine ratio?</h3>

The complete question is added as an attachment

Start by calculating the hypotenuse (h) using

h^2 = 5^2 + 12^2

Evaluate the exponent

h^2 = 25 + 144

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h^2 = 169

Evaluate the exponent of both sides

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The cosine ratio is then calculated as:

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This gives

cos(L) =5/13

Hence, the value of the cosine ratio cos(L) is 5/13