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Marizza181 [45]
3 years ago
8

A parabola has a vertex of (5,4) and goes through the point (6,-10)

Mathematics
1 answer:
natali 33 [55]3 years ago
5 0
Y = -2(x-5)^2 + 4

Note: vertex form is 0, f(x), y, or nothing= a(x-h)^2 + k
The opposite of the x value of the vertex is h
The y value value of the vertex is k.


Find a. Plug in (6,-10)

-10 = a(6-5)^2 + 4
-10 = 1a + 4
-10 = 5a
a = -2
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Plug 2 back into the equation and set it equal to 312.
2 \pi *4+2 \pi *2h = 312 \\ 4 \pi *h = 312-8 \pi \\ h =  \frac{312-8 \pi }{4 \pi } = 23
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