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Alinara [238K]
2 years ago
10

Felix is now six times as old as Debbie. In twelve years time Felix will be two times as old as Debbie. How old are they​

Mathematics
1 answer:
Minchanka [31]2 years ago
6 0

Step-by-step explanation:

let debbie be x years

let felix be 6x years

in 12 years felix will be 2x older than debbie

do the calc

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John ran of a mile in 8 minutes. If he continues running at that speed, how long will it take him to run one mile? A) 4 minutes
stich3 [128]

Answer:

The answer is D because, John is gonna keep running the multiples of 8.

Step-by-step explanation:

8X2= 16

3 0
2 years ago
What series of transformations that maps one triangle onto the other. What does this tell us about the triangles
Viefleur [7K]
I was thinking of answering this but its to complicated :/
4 0
3 years ago
Simplify this expression. 17 - 12x - 18 - 5x = ??​
jok3333 [9.3K]
17 -12x - 18 - 5x=
-1 - 17x =
-1 = 17x
3 0
3 years ago
Read 2 more answers
Find the sum of the positive integers less than 200 which are not multiples of 4 and 7​
taurus [48]

Answer:

12942 is the sum of positive integers between 1 (inclusive) and 199 (inclusive) that are not multiples of 4 and not multiples 7.

Step-by-step explanation:

For an arithmetic series with:

  • a_1 as the first term,
  • a_n as the last term, and
  • d as the common difference,

there would be \displaystyle \left(\frac{a_n - a_1}{d} + 1\right) terms, where as the sum would be \displaystyle \frac{1}{2}\, \displaystyle \underbrace{\left(\frac{a_n - a_1}{d} + 1\right)}_\text{number of terms}\, (a_1 + a_n).

Positive integers between 1 (inclusive) and 199 (inclusive) include:

1,\, 2,\, \dots,\, 199.

The common difference of this arithmetic series is 1. There would be (199 - 1) + 1 = 199 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times ((199 - 1) + 1) \times (1 + 199) = 19900 \end{aligned}.

Similarly, positive integers between 1 (inclusive) and 199 (inclusive) that are multiples of 4 include:

4,\, 8,\, \dots,\, 196.

The common difference of this arithmetic series is 4. There would be (196 - 4) / 4 + 1 = 49 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times 49 \times (4 + 196) = 4900 \end{aligned}

Positive integers between 1 (inclusive) and 199 (inclusive) that are multiples of 7 include:

7,\, 14,\, \dots,\, 196.

The common difference of this arithmetic series is 7. There would be (196 - 7) / 7 + 1 = 28 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times 28 \times (7 + 196) = 2842 \end{aligned}

Positive integers between 1 (inclusive) and 199 (inclusive) that are multiples of 28 (integers that are both multiples of 4 and multiples of 7) include:

28,\, 56,\, \dots,\, 196.

The common difference of this arithmetic series is 28. There would be (196 - 28) / 28 + 1 = 7 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times 7 \times (28 + 196) = 784 \end{aligned}.

The requested sum will be equal to:

  • the sum of all integers from 1 to 199,
  • minus the sum of all integer multiples of 4 between 1\! and 199\!, and the sum integer multiples of 7 between 1 and 199,
  • plus the sum of all integer multiples of 28 between 1 and 199- these numbers were subtracted twice in the previous step and should be added back to the sum once.

That is:

19900 - 4900 - 2842 + 784 = 12942.

8 0
3 years ago
45.50 is 30% of what number
m_a_m_a [10]

Answer:

31.85

Step-by-step explanation:

to subtract 30 percent from 45.50 just divide the percentage (30) by 100 subtract this value form 1 then multiply it by the initial value (45.50) so

final value = 45.50 x ( 1 - \frac{30}{100} )

final value = 45.50 x ( 1 - 0.3)

final value = 45.50 x (0.7)

final value = 31.85  

subtract 30% is the same as discount 30% this operation could be for example a 30% discount on 45.50

note: 0.3 can be found just by moving the decimal point 2 places to the left \frac{30}{100} = 0.3 as a decimal

3 0
2 years ago
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