I might be wrong but it should be 1
Answer:
Part A: That 6 pounds of rice costs $18
Part B: (1,3) represents the unit price
Part C: 4 pounds of rice, because $12/3 equals 4
Step-by-step explanation:
Part A: The first point, 6, is on the amount of rice axis and the second point, 18, is on the total cost axis.
Part B: The unit price means the price for just 1 of something, so if you go to 1 pound of rice on the graph, you see it's at 3 on the total cost axis. Which means that 1 pound of rice costs $3.
Part C: From Part B you know that 1 pound of rice equals $3. So if you spend $12, then you can divide that by $3 to see how many pounds of rice you bought. 12/3 equals 4, so you bought 4 pounds of rice. Or you can count by 3's until you get to 12: 3, 6, 9, 12. That's 4 times so that means you bought 4 pounds of rice.
The total cost was 116% of the original bill;
Original bill was;
= <span>$22.5</span>
It should be noted that the z score for Thomas test grade is 0.237.
<h3>How to illustrate the information?</h3>
From the information, Thomas took a test in Social Studies and earned a 74.8 and there is the fact that all the students' test grades in the Social Studies class had a mean of 72.6 and a standard deviation of 9.3,
Therefore, the z score for Thomas test grade will be:
= Test score - Mean / Standard deviation
= 74.8 - 72.6 / 9.3
= 0.237.
Therefore, it should be noted that the z score for Thomas test grade is 0.237.
Learn more about standard deviation on:
brainly.com/question/12402189
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Thomas and Pablo began arguing about who did better on their tests, but they couldn't decide who did better given that they took different tests. Thomas took a test in Social Studies and earned a 74.8, and Pablo took a test in Science and earned a 64.1. Use the fact that all the students' test grades in the Social Studies class had a mean of 72.6 and a standard deviation of 9.3, and all the students' test grades in Science had a mean of 61.1 and a standard deviation of 9.8 to answer the following questions.
Calculate the z score for Thomas test grade.
