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3 years ago

Helppp pls for the 2 people willing to help .

Mathematics

1 answer:

Shtirlitz [24]3 years ago

7 0

Step-by-step explanation: I honestly am too lazy to solve but I will tell you what to do. For number 1-5 you need the amount (a) divided by the Tax/Tip/%off/Discount(d). Whatever that number is (t), you subtract that from a to get the total cost which is (c) So in other words - a-d=t a-t=c UWU

Then onto the next ones. Number 6: First you do 11/2800. Thats the 11%. Next you get 67,530 divide that by that last number you got. Then multiply that by 2800. Then there is your answer

Okay so next one Number 7: Same thing as the other one actually -v-

Next answer mate! Number 8: 3400 x4 + (3400/3.5) x 4= ???? You tell me that ;)

We almost doneeee Number 9: 20460 x 5 + (20460/5.5) x 5= ____ Hhehehehe last one mateyyyy

We actually at the last one. Its been fun helping you! :) Number 10: 35000/7 then whatever that is times 5. I enjoyed going back in my little kid brain tohelp you :)

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Enter your answer and show all the steps that you use to solve this problem.

slamgirl [31]

Answer:

h = -t+20

After 8 hours the candle will be 12 inches

Step-by-step explanation:

We have 2 points (time, inches)

(3,17) and (5,15)

We can find the slope

m = (y2-y1)/(x2-x1)

= (15-17)/(5-3)

= -2/2

= -1

We can use point slope form

y-y1 = m(x-x1)

Replace y with h and x with t

h-17 = -1 (t-3)

Distribute

h-17 = -t+3

Add 17 to each side

h-17+17 = -t+3+17

h = -t+20

3 0

3 years ago

Which completely describes the polygon

olga2289 [7]

A=equilateral hope that helped

6 0

3 years ago

Each of a group of 20 intermediate tennis players is given two rackets, one having nylon strings and the other synthetic gut str

sergeinik [125]

Answer:

Find answers below

Step-by-step explanation:

H0: P <= 0.5

Ha: P > 0.5

, the number who prefer gut strings is <= a number or the test tends towards the left-tailed.

{0,1,2,3,4,5} ;

{15,16,17,18,19,20} is a right-tailed test and not appropriate for H0:

{ 0,1,2,3,17,18,19,20} is two-tailed and not appropriate for H0:

Does the region specify a level .05 test? No

P = proportion who prefer gut strings to nylon

P = X /20

Assume alpha = 0.05

z(alpha) = -1.645

Reject if (x/20 - 0.5) / sqrt[ (0.5)(0.5)/20 ] < -1.645

Reject if (x/20 - 0.5) < < (-1.645) sqrt ( (0.5)(0.5)/20 )

Reject if x/20 < (-1.645) sqrt ( (0.5)(0.5)/20 ) + 0.5

Reject if x/20 < 0.316

Reject if x < (0.316)(20) = 6.32

{0,1,2,3,4,5,6} is the region for the best level 0.05 test

According to (a), reject H0 if x <= 5

P( Type II error) = P( do not reject H0/ when Ha is true)

P( Type II error) = P( x > 5/ P=0.6)

x ---p(x)

6 0.004854 0.998388

7 0.014563

8 0.035497

9 0.070995

10 0.117142

11 0.159738

12 0.179706

13 0.165882

14 0.124412

15 0.074647

16 0.034991

17 0.012350

18 0.003087

19 0.000487

20 0.000037

add: 0.9984 -- proba bility of a type II error

Assuming P=0.8

P( Type II error) = P( x > 5/ P=0.8)

6 0.000002 1.000000

7 0.000013

8 0.000087

9 0.000462

10 0.002031

11 0.007387

12 0.022161

13 0.054550

14 0.109100

15 0.174560

16 0.218199

17 0.205364

18 0.136909

19 0.057646

20 0.011529

add: 1.0000 probability of a type II error

P( x <= 13) =

0 0.000001

1 0.000019

2 0.000181

3 0.001087

4 0.004621

5 0.014786

6 0.036964

7 0.073929

8 0.120134

9 0.160179

10 0.176197

11 0.160179

12 0.120134

13 0.073929

add: 0.9423 < 0.10 , H0 cannot be rejected

5 0

3 years ago

A ball is thrown into the air by a baby alien on a planet in the system of Alpha Centauri with a velocity of 43 ft/s. Its height

Lina20 [59]

Answer:

Instantaneous Velocity at t = 1 is 20 feet per second

Step-by-step explanation:

We are given he following information in the question:

$y(t)=43t-23t^{2}$

B) Instantaneous Velocity at t = 1

$y(1) = 43(1)-23(1)^2 = 20$

A) Formula:

Average velocity =

$\displaystyle\frac{\text{Displacement}}{\text{Time}}$

1) 0.01

$y(1 + 0.01)=y(1.01) = 43(1.01)-23(1.01)^{2} = 19.9677\\\\\text{Average Velocity} = \dfrac{y(1.01)-y(1)}{1.01-1} =\dfrac{19.9677-20}{1.01-1}= \dfrac{-0.0323}{0.01} = -3.230000 \text{feet per second}$

2) 0.005 s

$y(1 + 0.005)=y(1.005) = 43(1.005)-23(1.005)^{2} = 19.984425\\\\\text{Average Velocity} = \dfrac{y(1.005)-y(1)}{1.005-1} =\dfrac{19.984425-20}{1.005-1} = -3.1150000 \text{feet per second}$

3) 0.002 s

$y(1 + 0.002)=y(1.002) = 43(1.002)-23(1.002)^{2} = 19.993908\\\\\text{Average Velocity} = \dfrac{y(1.002)-y(1)}{1.002-1} =\dfrac{19.993908-20}{1.002-1} = -3.0460000 \text{feet per second}$

4) 0.001 s

$y(1 + 0.001)=y(1.001) = 43(1.001)-23(1.001)^{2} = 19.996977\\\\\text{Average Velocity} = \dfrac{y(1.001)-y(1)}{1.001-1} =\frac{19.996977-20}{1.001-1} = -3.0230000 \text{feet per second}$

3 0

3 years ago

Suppose you school costs for this term were $4640 and financial aid covered 4/5 of that amount?

Salsk061 [2.6K]

Answer:

Covered: $3712

Still need to pay: $928

Step-by-step explanation:

4/5 --> 0.8 --> 80%

4640 x 0.8 --> 3712

Covered: $3712 (which is 80%)

Still need to pay: $928 (which is 20%)

3 0

3 years ago