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Black_prince [1.1K]
3 years ago
12

How do I write this as a math equation: it's number 13

Mathematics
1 answer:
STALIN [3.7K]3 years ago
3 0
3 (2-x) = 8
is the equation because its says 3 times 2 decreased (minus) x equals 8
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Hans deposits $300 into an account that pays simple interest at a rate of 2% per year. How much interest will he be paid in the
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300 x 0.02 x 5 = 30
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<span> interest will $30 in the first 5 years</span>
5 0
3 years ago
Latrell is comparing two job opportunities one job will pay $12 an hour and he will work 40 hour a week. The other one pays an a
Nata [24]

To compare these two jobs, you need to have a common point. In this problem, you have to solve for the annual salary of the first job and compare it with the annual salary of the second job which is already given.

$12 per hour x 40 hours per week x 48 weeks in a year = $23,040

First job’s annual salary is $23,040

Second job’s annual salary is $22,000

Therefore, the job which pays $12 an hour pays more.

7 0
3 years ago
Which number has the greatest absolute value?
Rasek [7]

Answer:

|-8|

if you are happy with my answer, please give brainliest :)

Step-by-step explanation:

Absolute value of -8 is 8, which is greater than the other values.

8 0
3 years ago
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Two buses leave a station at the same time and travel in opposite directions. One bus travels 17 mi/h slower than the other. If
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Answer:

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3 0
2 years ago
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The marketing director of a large department store wants to estimate the average number of customers who enter the store every f
Dahasolnce [82]

Answer:

36.5674\leq x'\leq61.4326

Step-by-step explanation:

If we assume that the number of arrivals is normally distributed and we don't know the population standard deviation, we can calculated a 95% confidence interval to estimate the mean value as:

x-t_{\alpha /2}\frac{s}{\sqrt{n} } \leq x'\leq x-t_{\alpha /2}\frac{s}{\sqrt{n} }

where x' is the population mean value, x is the sample mean value, s is the sample standard deviation, n is the size of the sample, \alpha is equal to 0.05 (it is calculated as: 1 - 0.95) and  t_{\alpha /2} is the t value with n-1 degrees of freedom that let a probability of \alpha/2 on the right tail.

So, replacing the mean of the sample by 49, the standard deviation of the sample by 17.38, n by 10 and t_{\alpha /2} by 2.2621 we get:

49-2.2621\frac{17.38}{\sqrt{10} } \leq x'\leq 49+2.2621\frac{17.38}{\sqrt{10} }\\49-12.4326\leq x'\leq 49+12.4326\\36.5674\leq x'\leq61.4326

Finally, the interval values that she get is:

36.5674\leq x'\leq61.4326

8 0
3 years ago
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