Answer: the number of variations in sign = 3
Step-by-step explanation:
Let the finite sequence 1, –3, 2, 5, –4, –6 , the only pairs of consecutive terms for which the product of the two consecutive terms is negative are :
{1, –3} ; {–3, 2}; {5, –4} then
the number of variations in sign = 3
B
Locate the point 6 on the x-axis
Any point to the left of 6 has an x-coordinate less than 6 while every point to the right of 6 has an x-coordinate greater than 6
The points to the right of 6 are Z and L
The mode is the number that occurs the most, in this case, 78 appears 3 times which means 78 is the mode
Answer:
I think this is the answer
