Answer:
The amount invested at 6% is $12,857.14
The amount invested at 13% is $17,142.86
Step-by-step explanation:
Let
x ----> the amount invested at 6%
30,000-x -----> the amount invested at 13%
we know that
The interest earned by the amount invested at 6% plus the interest earned by the amount at 13% must be equal to the interest earned by the total amount of $30,000 at 10%
Remember that



so
The linear equation that represent this situation is

solve for x


therefore
The amount invested at 6% is $12,857.14
The amount invested at 13% is $17,142.86