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Stells [14]
3 years ago
13

!!!!!!!!!!!HELP ASAP!!!!!!!

Mathematics
2 answers:
stich3 [128]3 years ago
6 0

Answer:

X=-33

Step-by-step explanation:

Comine multiplied terms into a single fraction 2(x+6)/3=-18

distribute 2x+13/3=-18

multiply all terms by the same value to eleminate fraction denominators 3(2x+12/3)=3(-18)

simplify 2x+12=-54

subtract 12 from both sides of the eqaution 2x+12-12=-54-12

simplify 2x=-66

divide both sides of the eqautions by the same term 2x/2=-66/2

simplify x=-33

stepladder [879]3 years ago
3 0

Answer:

x = -33

Step-by-step explanation:

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A straight line has a slope of 2.08. Calculate the angle that the line makes with the x (horizontal) axis.
zubka84 [21]

Answer:

The angle that the line makes with x-axis of of 64.3º.

Step-by-step explanation:

Equation of a line, and angle with the x axis:

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The angle that the line makes with the x axis is given by the angle which has tangent m, that is, a = \tan^{-1}{m}.

In this question:

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3 years ago
in a random sample of 200 people, 154 said that they watched educational television. fine the 90% confidence interval of the tru
melisa1 [442]

Answer:

[0.7210,0.8189] = [72.10%, 81.89%]

Step-by-step explanation:

The sample size is  

n = 200

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<em>Since both np ≥ 10 and n(1-p) ≥ 10 </em>

<em>We can approximate this discrete binomial distribution with the continuous Normal distribution. As the sample size is large enough, not applying the continuity correction factor makes no significant  difference. </em>

The approximation would be to a Normal curve with this parameters:

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<em>Standard deviation </em>

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The 90% confidence interval for the proportion would be then  

\bf  [0.77-z^*0.0298, 0.77+z^*0.0298]

where \bf z^* is the 10% critical value for the Normal N(0,1) distribution , this is a value such that the area under the N(0,1) curve outside the interval \bf [-z^*,z^*] is 10%=0.1

We can either use a table, a calculator or a spreadsheet to get this value.

In Excel or OpenOffice Calc we use the function

<em>NORMSINV(0.95) and we get a value of 1.645 </em>

The 90% confidence interval for the proportion is then

\bf  [0.77-1.645^*0.0298, 0.77+1.645^*0.0298]=[0.7210,0.8189]

This means there is a 90% probability that the proportion of people who watch educational television is between 72.10% and 81.89%

If the television company wanted to publicize the proportion of viewers, do you think it should use the 90% confidence interval?

Yes, I do.

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