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lys-0071 [83]
3 years ago
7

Which number has a 5 that represents a value one thousand times greater than the value represented by the 5 in 41,253?

Mathematics
1 answer:
Dmitrij [34]3 years ago
4 0

Answer:

B) 45,523

Hope this is correct

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Write a linear function f with f(0)=3 and f(−6)=3
Dima020 [189]

Answer:

y = 3

Step-by-step explanation:

Slope = 0/-6 = 0

y-int. = 3

8 0
3 years ago
What would be the answer???
nignag [31]

Answer:

120

Step-by-step explanation:

The sum of the angles in a quadrilateral is 360 degrees

2t+t+2t+t = 360

6t = 360

Divide by 6

6t/6 = 360/6

t = 60

Angle Z = 2t

Angle Z = 2*60 = 120

7 0
4 years ago
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Can someone help me? Will mark brainlist!
inna [77]

Answer:

The total surface area for the left block is 235.2

Step-by-step explanation:

multiply all the sides then add them together

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3 years ago
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Question #1 What is the sum?​
sweet-ann [11.9K]

Answer:

\frac{7}{a + 8}+\frac{7}{a^2-64} = \frac{14}{a^2+a-56}

Step-by-step explanation:

Sum means finding the total of something. We can do this by using addition.

\frac{7}{a + 8}+\frac{7}{a^2-64}

In this problem, we will add the numerators and the denominators.

\frac{(7+7)}{(a+8)+(a^2-64)}

\frac{14}{a^2+a-56}

So, your answer is letter choice B.

5 0
3 years ago
g The fencing of the left border costs $10 per foot, while the fencing of the lower border costs $2 per foot. (No fencing is req
klio [65]

Answer:

Area = 1690ft^2\\x = 130ft, y = 26ft

Step-by-step explanation:

Given the costs we can form an equation:

10y + 2x =520 - Eq(A)

and fencing is triangular such that the area enclosed can be written as:

A = \dfrac{xy}{2} -Eq(B)

  • First need to convert the above equation so that it is only in terms of one variable. [either x or y]

To make the equation only in terms of x we can substitute y from Eq(A) i.e, y =\frac{520-2x}{10}, to Eq(B)

A = \dfrac{x}{2} \dfrac{520-2x}{10}

simplify

A = \dfrac{520x - 2x^2}{20}

A = -\dfrac{1}{10}x^2 + 26x

  • Now, in order to find the maximum area enclosed we can find \frac{dA}{dx} and equate it zero.

\dfrac{dA}{dx} = -\dfrac{1}{5}x + 26

0 = -\dfrac{1}{5}x + 26

-26 = -\dfrac{1}{5}x

x = 130

we have the length of one dimension: specifically, the lower fence will be x =130ft

we can use this value of x to find the corresponding value of y. From Eq(A)

10y + 2x =520

10y +2(130) = 520

y = \dfrac{520 - 2(130)}{10}

y = 26

the length of the left fence will be y =26ft

  • The enclosed area by the fence will be

A = \dfrac{xy}{2}

A = \dfrac{(130)(26)}{2}

A = 1690

Hence the maximum area that can enclosed by the fences provided the costs will be 1690ft^2

  • You can even check the cost of the dimensions whether they all add up to $520 or not.

Use Eq(A)

10y + 2x =520

10(26) + 2(130) =520

and indeed it does!

5 0
3 years ago
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