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3 years ago

Music lessons cost $20 per week. How much do 6 weeks of lessons cost? i need the expression

Mathematics

2 answers:

Feliz [49]3 years ago

8 0

20x
20 ( cost per week )
x ( amount of weeks )
20 x 6 = $120

Darya [45]3 years ago

7 0

Answer:

20+20+20+20+20+20= 120

Step-by-step explanation:

2^6 = 120 hope this helps! plz mark brainliest

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Consider a discrete random variable x with pmf px (1) = c 3 ; px (2) = c 6 ; px (5) = c 3 and 0 otherwise, where c is a positive

PtichkaEL [24]

Looks like the PMF is supposed to be

$\mathbb P(X=x)=\begin{cases}\dfrac c3&\text{for }x\in\{1,5\}\\\\\dfrac c6&\text{for }x=2\\\\0&\text{otherwise}\end{cases}$

which is kinda weird, but it's not entirely clear what you meant...

Anyway, assuming the PMF above, for this to be a valid PMF, we need the probabilities of all events to sum to 1:

$\displaystyle\sum_{x\in\{1,2,5\}}\mathbb P(X=x)=\dfrac c3+\dfrac c6+\dfrac c3=\dfrac{5c}6=1\implies c=\dfrac65$

Next,

$\mathbb P(X>2)=\mathbb P(X=5)=\dfrac c3=\dfrac25$

$\mathbb E(X)=\displaystyle\sum_{x\in\{1,2,5\}}x\,\mathbb P(X=x)=\dfrac c3+\dfrac{2c}6+\dfrac{5c}3=\dfrac{7c}3=\dfrac{14}5$

$\mathbb V(X)=\mathbb E\bigg((X-\mathbb E(X))^2\bigg)=\mathbb E(X^2)-\mathbb E(X)^2$
$\mathbb E(X^2)=\displaystyle\sum_{x\in\{1,2,5\}}x^2\,\mathbb P(X=x)=\dfrac c3+\dfrac{4c}6+\dfrac{25c}3=\dfrac{28c}3=\dfrac{56}5$
$\implies\mathbb V(X)=\dfrac{56}5-\left(\dfrac{14}5\right)^2=\dfrac{84}{25}$

If $Y=X^2+1$ , then $X^2=Y-1\implies X=\sqrt{Y-1}$ , where we take the positive root because we know $X$ can only take on positive values, namely 1, 2, and 5. Correspondingly, we know that $Y$ can take on the values $1^2+1=2$ , $2^2+1=5$ , and $5^2+1=26$ . At these values of $Y$ , we would have the same probability as we did for the respective value of $X$ . That is,

$\mathbb P(Y=y)=\begin{cases}\dfrac c3&\text{for }y=2\\\\\dfrac c6&\text{for }y=5\\\\\dfrac c3&\text{for }y=26\\\\0&\text{otherwise}\end{cases}$

Part (5) is incomplete, so I'll stop here.

8 0

3 years ago

If two lines do not intersect , then their intersection is not exactly one point.

Dvinal [7]

If they don't intersect then there is no solution and the lines are parrell.

8 0

3 years ago

Four points are placed on a circle. How many segments will it take to connect each point to every other point?

alexandr1967 [171]

Answer:

6 segments are required to connect each point to every other point.

Step-by-step explanation:

If four points are placed on a circle.Then as we know the segment is a line that join two points.

Now as we are given four points on the circle.

so we will firstly start with the first point; the first point requires 3 segments to connect to the remaining three points.
Next second point will just require 2 segments to connect to the two points as it is already connected to the first point.
similarly third point requires just one segment to connect to the last point as it is already connected to first and second point as done above.
and hence by the above three steps the fourth point is connected to all the points.

Hence, 6 segments are required to connect each point to every other point.

3 0

3 years ago

Read 2 more answers

YOU KNOW THAT THE SUM OF THE ANGLES IN A QUADRILATERAL IS 360 DECREES. HOW CAN THIS HELP YOU REMEMBER THAT THE SUM OF THE ANGLES

gtnhenbr [62]

Answer:

that can help because all you need to remember is that the sum of the angles in a triangle is half of the sum of the angles that add up in a quadrilateral.

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2 years ago

write a story problem that can be solved by finding the sum of 506,211 and 424,809. then solve the problem

Amiraneli [1.4K]

<u>Story Problem</u>

Mr. Bill Gates bought a house in Italy for $\$506,211$ and a house in Canada for $\$424,809$ . What is the total cost of the two houses?