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Alik [6]
3 years ago
10

(8x+2)+(9x+3). Solve for x Need ASAP it’s for exam

Mathematics
1 answer:
Pavel [41]3 years ago
6 0

Answer:

17x+5

Step-by-step explanation:

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The numerator of a fraction is 9 and the denominator is 6. All of the following numbers are equivalent except ____.
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2/3 Hass to be the answer because the larger number nine would be on top as the numerator. Therefore, I know this without even having to simplify. Hope this helps :-)
5 0
3 years ago
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Georgia [21]

Answer:

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5 0
3 years ago
Use the binomial expression (p+q)^n to calculate a binomial distribution with n=5 and p=0.3.(Show all steps)
Helen [10]

Answer:

The binomial in expanded form is (0.3 + q)^{5} = \frac{243}{100000} + \frac{81}{2000}\cdot q + \frac{27}{100}\cdot q^{2} + \frac{9}{10} \cdot q^{3} + \frac{3}{2}\cdot q^{4} + q^{5}.

Step-by-step explanation:

The Binomial Theorem states that a binomial of the form (a + b)^{n} can be expanded by using the following identity:

(a + b)^{n} = \Sigma \limits^{n}_{k = 0}\,\frac{n!}{k!\cdot (n-k)!}\cdot a^{n-k}\cdot b^{k} (1)

If we know that a = p = 0.3 and n = 5, then the expanded form of the binomial is:

(p+q)^{n} = \frac{243}{100000} + 5\cdot \left(\frac{81}{10000} \right)\cdot q + 10\cdot \left(\frac{27}{1000})\cdot q^{2} + 10\cdot \left(\frac{9}{100} \right)\cdot q^{3} + 5\cdot \left(\frac{3}{10} \right)\cdot q^{4} + q^{5}

(0.3 + q)^{5} = \frac{243}{100000} + \frac{81}{2000}\cdot q + \frac{27}{100}\cdot q^{2} + \frac{9}{10} \cdot q^{3} + \frac{3}{2}\cdot q^{4} + q^{5}

8 0
3 years ago
James wants to compete in the international speed texting competition next year where participants compete on text speed and acc
lions [1.4K]

Complete question :

James wants to compete in the international speed texting competition next year where participants compete on text speed and accuracy. James’s current text speed is 2 characters per second. James has found that his texting speed increases at a rate of 1⁄2 a character per second for each month that he practices.

1. a. What is James’s new texting speed if he practices for only 1 month? __________

b. What is James’s new texting speed if he practices for 2 months? ____________

c. What is his new texting speed if he practices for 3 months? _____________

d. Write an algebraic equation that gives James’s texting speed s for m months of

practice.

Answer:

2 1/2 ; 3, 3 1/2 ; s = 2 + 1/2m

Step-by-step explanation:

Given that :

Speed = 2 characters per second

Rate of change = 1/2 character per second increase per month

New texting speed after 1 month :

Initial speed + (change per month * number of months)

2 + 1/2 * 1

= 2 1/2 or 2.5

After 2 months :

Initial speed + (change per month * number of months)

2 + (1/2 * 2)

2 + 1

= 3 characters per second :

After 3 months :

Initial speed + (change per month * number of months)

2 + 1/2 * 3

= 2 + 1.5

= 3.5

For the algebraic equation :

New texting speed, s

Number of months, m

Initial speed + (change per month * number of months)

s = 2 + 1/2 * m

s = 2 + 1/2m

4 0
3 years ago
The slope is 2.92, which shows a positive relationship because it is a positive number. The
Alona [7]
Yes it does make sense.
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3 years ago
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