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alexandr402 [8]
3 years ago
7

Josh volunteered at the zoo for 14 hours in one month. This was 3 1/2 times as many hours as Gina volunteered. How many hours di

d Gina volunteer?
Mathematics
2 answers:
maria [59]3 years ago
6 0


I think 4

14 divided by 3.5 = 4


jonny [76]3 years ago
5 0
This one you can't really make a formula for or anything, but it's fairly simple to figure out, with a bit of guess and check.
14 is really close to 15, but that's bigger, so let's try a smaller number that would work.
It has to be divisible by 2, because you've got a whole number that is 3 1/2 times the other number. (1/2 of a whole number means it's divisible by 2).
10 is divisible by 2,
10 ÷ 2 = 5
But, 10 x 3 = 30 which is much bigger than 14.
So, we've got to start with a smaller number.
Let's try something really small, like 4. We could try 2, but 2 x 3 = 6, which, even with 1/2 of 2, isn't nearly close to 14.
Now, 4 x 3 = 12
That's quite close to 14.
And 1/2 of 4 is 2.
All we do now is add 12 to 2 and see if it works.
12 + 2 = 14
14 = 14
This one works.
That means that Gina volunteered for 4 hours, because 3 1/2 x 4 = 14.
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The graph below represents which systems of inequalities?​
SashulF [63]

Answer:

Step-by-step explanation:

y > - x + 3

y ≤ 2x - 2

3 0
2 years ago
find the coordinate of U' after a 90° counterclockwise rotation of the triangle about the origin and then a translation of 2 uni
SVETLANKA909090 [29]

Answer: U' = (0, 1)

<u>Step-by-step explanation:</u>

U = (3, -5)

rotate 90° counterclockwise means (x, y) = (-y, x)

new U = (5, 3)

down 2 units means subtract 2 from the y-coordinate

newer U = (5, 1)

left 5 units means subtract 5 from the x-coordinate

U' = (0, 1)

6 0
2 years ago
Of 575 broiler chickens purchased from various kinds of food stores in different regions of a country and tested for types of ba
chubhunter [2.5K]

Answer:

a) 0.68 - 2.58 \sqrt{\frac{0.68(1-0.68)}{575}}=0.630  

0.68 + 2.58 \sqrt{\frac{0.68(1-0.68)}{575}}=0.730  

And the 99% confidence interval would be given (0.630;0.730).  

b) We are 99% confident that the true proportion of infected chickens are between 0.63 (63%) and 0.73 (73%)

c) For this case the answer would be No. Since all the required assumptions in order to construct the confidence interval  are satisfied, so then the results can be assumed for all the population

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

p represent the real population proportion of interest  

\hat p =0.68 represent the estimated proportion

n=575 is the sample size required (variable of interest)  

z represent the critical value for the margin of error  

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})  

Part a

The confidence interval would be given by this formula  

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}  

For the 99% confidence interval the value of \alpha=1-0.99=0.01 and \alpha/2=0.005, with that value we can find the quantile required for the interval in the normal standard distribution.  

z_{\alpha/2}=2.58  

And replacing into the confidence interval formula we got:  

0.68 - 2.58 \sqrt{\frac{0.68(1-0.68)}{575}}=0.630  

0.68 + 2.58 \sqrt{\frac{0.68(1-0.68)}{575}}=0.730  

And the 99% confidence interval would be given (0.630;0.730).  

Part b

We are 99% confident that the true proportion of infected chickens are between 0.63 (63%) and 0.73 (73%)

Part c

For this case the answer would be No. Since all the required assumptions in order to construct the confidence interval  are satisfied, so then the results can be assumed for all the population

4 0
3 years ago
Solve for x, rounding to the nearest hundredth.<br> 10^3x = 98
Anna71 [15]

Answer:

see explanation

Step-by-step explanation:

10^3x=98

1000x=98

x=98/1000

x=49/500

x=0.98

if it is rounded to the nearest hundredth then x=0

8 0
3 years ago
What is the maximum number of possible extreme values for the function,<br> f(x) = х2 -7x – 6?
timama [110]

Answer:

Only one extreme value of f(x) is possible.

Step-by-step explanation:

We are given the quadratic function of independent variable x which is f(x) = x² - 7x - 6 ......(1)

Now. the condition for extreme values of f(x) is \frac{df(x)}{dx} =0

Hence, differentiating both sides of equation (1) with respect to x, we get

\frac{df(x)}{dx} = 2x -7 = 0

⇒ x = 3.5.

So there is only one value of x for which f(x) has extreme value which is x = 3.5.

Therefore, only one extreme value of the given function is possible. (Answer)

3 0
3 years ago
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