All categories

4 years ago

What is the square root of 30 in simplified form

Mathematics

2 answers:

UkoKoshka [18]4 years ago

8 0

5X square root of 6 is the correct answer

rewona [7]4 years ago

6 0

The square root of 30 in its simplest form is 5.5 ( I think)

You might be interested in

Change 3/4 into its equivalent decimal form

svet-max [94.6K]

That would be 0.75:) hope this helps!

6 0

3 years ago

Read 2 more answers

PLEASE HELP QUICK I AM IN A RUSH

Alekssandra [29.7K]

C because it simplifies to 0=0 which proves that it has infinite solutions!

7 0

3 years ago

Read 2 more answers

Find the terminal point on the unit circle determined by pi radians.

svet-max [94.6K]

Answer:

Terminal points

$(x,y) = (\frac{1}{\sqrt{2} }) , (\frac{-1}{\sqrt{2} })$

Step-by-step explanation:

According to the question, it is provided that

$\theta = \frac{7\pi}{4}$

Now

$x = 1. cos (\frac{7\pi}{4})\\\\ = cos (2\pi - \frac{\pi}{4})\\\\= cos \frac{\pi}{4} \\\\= \frac{1}{\sqrt{2} }$

$y = 1. sin (\frac{7\pi}{4})\\\\ = sin (2\pi - \frac{\pi}{4})\\\\= -sin \frac{\pi}{4} \\\\= \frac{-1}{\sqrt{2} }$

Now

$(x,y) = (\frac{1}{\sqrt{2} }) , (\frac{-1}{\sqrt{2} })$

These two represents the terminal points

We simply applied the above equations and then equate these two equations to determine the terminal points and therefore the same is to be considered

It could be figure out by using the x and y points

Therefore the two shows the terminal points

3 0

3 years ago

Help me out plssssss and thanks !!!!!!!

Drupady [299]

Answer:

arc AB = 142

Step-by-step explanation:

The angle of AB is 180 -38 = 142

The arc is the same measure since the angle is a central angle

arc AB = 142

5 0

3 years ago

The area of triangle abc is 6 square centimeters. Ab is parallel to de . Bd=4bc . What is the number of square centimeters in th

cestrela7 [59]

It is given that area( Δ ab c) =6 square units.

Also ab║d e

⇒b d =4 b c

I have depicted picture below.

Consider Δ cde in which points a and b are in the interior such that ab║de.

So, as you know that if in a triangle line joining two points is parallel to third side then the two sides are proportional.i.e

⇒ca/ae =cb / bd

Also, ∠ c is common.

∴Δcab is similar to Δ cde.

As we know if ratio of areas of two similar triangles is square of their corresponding sides.

= $\frac{Ar(Δcab)}{Ar(Δcde)}=[\frac{cb}{bd}]^2$

⇒6/Δcde =1/4

⇒Ar (Δ cde)=6×4

Ar (Δ cde) =24 square centimeter

5 0

3 years ago