Answer:
y (is less than or equal to) 3
Step-by-step explanation:
i hope this helps :)
I: 12x-5y=0
II:(x+12)^2+(y-5)^2=169
with I:
12x=5y
x=(5/12)y
-> substitute x in II:
((5/12)y+12)^2+(y-5)^2=169
(25/144)y^2+10y+144+y^2-10y+25=169
(25/144)y^2+y^2+10y-10y+144+25=169
(25/144)y^2+y^2+144+25=169
(25/144)y^2+y^2+169=169
(25/144)y^2+y^2=0
y^2=0
y=0
insert into I:
12x=0
x=0
-> only intersection is at (0,0) = option B
Answer:
-22y+27
Step-by-step explanation:
(4y-9)(2y-3)
<u>Distribute:</u>
8y-12y-18y+27
<u>Combine like terms:</u>
8y-12y-18y=-22y
-22y+27
Rotation dilation translation reflection
