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Mamont248 [21]
3 years ago
15

PLZ answer this question y-5 ≥ -15

Mathematics
2 answers:
aalyn [17]3 years ago
8 0

Answer:

y (is less than or equal to) 3

Step-by-step explanation:

i hope this helps :)

Crank3 years ago
3 0

Answer:

y <u>></u> -10

Step-by-step explanation:

y - 5 <u>></u> -15, you need to get y by itself, so you need to add 5 to both sides.

you are left with y <u>></u> -10

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Find value of X, please !!
Drupady [299]

Answer:

x=25

Step-by-step explanation:

60+70=130

180-130=50

50/2=25

4 0
4 years ago
Read 2 more answers
1) What is the equation of the line whose y-intercept is 3 and slope is 1?
s2008m [1.1K]
The\ slope-intercept\ form:y=mx+b\\\\m\ is\ slope\\b\ is\ y-intercept\\\\m=1;\ b=3\ then\ y=1x+3\Rightarrow y=x+3
5 0
3 years ago
Read 2 more answers
Include parentheses in your answer.<br> (x3 + y3) ÷ (x - y)
-Dominant- [34]
I'm assuming you mean \frac{x^3+y^3}{x-y}

we can factor that sum of perfect cubes from x^2+y^3 into (x+y)(x^2-xy+y^2)

so therefor \frac{x^3+y^3}{x-y}=\frac{(x+y)(x^2-xy+y^2)}{x-y}
that is simpliest form

8 0
3 years ago
Select the correct answer. What is the solution to this equation? A. B. C. D.
amm1812

Answer:

We do not have any problem to solve?

Step-by-step explanation:

3 0
2 years ago
write the equation of the line using the given information. type your awnser in slope intercept form,y=mx+b​
faltersainse [42]

Answer:

y=3/-1x+4

Step-by-step explanation:

Okay so first thing you need to know is that if there is an ordered pair (x, y) where x is 0, your y-intercept is your y. For example, your problem has (0, 4) your x is 0 and your y is 4. Therefore your y-intercept is 4 which is the b. To find your mx, or slope, you need to do (y2-y1)/(x2-x1). Your y2 will be your y in your second ordered pair and your y1 will be in your y in the first ordered pair. Same for your x. So, (4-1)/(0-1) which equals 3/-1. 3/-1 is your slope. So, your answer in slop intercept form is: y= 3/-1x+4. You could also try y= -3x+4 if that makes you more comfortable.

I know this is long this is my first time doing this lol.  

5 0
3 years ago
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