Given:
The arithmetic sequence is −15, −33, −51, −69.
To find:
The nth term of the arithmetic sequence.
Solution:
We have,
−15, −33, −51, −69
Here,
First term: a = -15
Common difference is
Now, nth term of an arithmetic sequence is
Substitute a=-15 and d=-18.
Therefore, the nth term of the given arithmetic sequence is .
14^(7x) = 17^(-8-x)
Take the log of both sides:
7x*log 14 = -(8+x)*log 17, or 7x^log 14 = -8*log 17 - x*log 17.
Grouping the x terms, we get x(7*log 14 + log 17)= -8*log 17
Then:
-8*log 17
x= -------------------------- (answer)
7*log 14 + log 17
Answer:
- -6x² - 6 = -7x - 9
- -6x² + 7x - 6 + 9 = 0
- -6x² + 7x + 3 = 0
- 6x² - 7x - 3 = 0
<u>Discriminant:</u>
- D = (-7)² - 4*6*(-3) = 49 + 72 = 121
<u>Since D > 0, there are 2 real solutions:</u>
- x = (- (-7) ±√121 )/12
- x = (7 ± 11)/12
- x = 1.5, x = -1/3
Answer:
The answer is $480
Step-by-step explanation:
1,200 multiplied by 5% = 60 and 60 multiplied by 8 = 480
Answer:
i need more space to send the pic i did the math tho
Step-by-step explanation:
