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Bas_tet [7]
3 years ago
14

I need help with this question and I will give brainliest

Mathematics
1 answer:
avanturin [10]3 years ago
8 0

Answer:

54°

Step-by-step explanation:

The two strokes on each side of the triangle show that the triangle is an isosceles triangle and ∠KJL and ∠KLJ are equal. The sum of angles in a triangle is 180°.

∠KJL + ∠KLJ = 180° - 72°

                     = 108°

∠KJL = 108° ÷ 2

         = 54°

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Pencils cost $.30 an I have five dollars how many can I by
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You can buy 16.6666666 or 16

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7 0
3 years ago
Write a word problem that can be solved using 25+0.5 X is less than or greater to 60
Tatiana [17]
Matt is having a lemonade stand and he needs $60 for a school fundraiser. he already has $25, but he needs more. If hes selling lemonade for $0.50 each cup, write an equation that shows how much money he needs to get at least $60.


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7 0
3 years ago
Is birth a qualitative or quantitative?<br><br> Birth year
7nadin3 [17]

Answer:

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Step-by-step explanation:

7 0
3 years ago
can i get some help? i tried figuring it out myself already but i must have done something wrong. please help!
zaharov [31]

First, we'll set up two equations. One for the amount of each coin and another for the value of the coins.

N will represent nickels

D will represent dimes

N + D = 30

---The problem tells us that there are 30 total coins

0.05N + 0.10D = 2.95

---Nickels are worth 5 cents and dimes are worth 10 cents, and the total value of the coins is 2.95

Now that we have our equations, we need to solve for one of the variables in the first equation. I will solve for N.

N + D = 30

N = 30 - D

Then, we take that equation and substitute our new value for N into the second equation (value) and solve for D.

0.05(30 - D) + 0.10D = 2.95

1.5 - 0.05D + 0.10D = 2.95

1.5 + 0.05D = 2.95

0.05D = 1.45

D = 29

Now that we know how many dimes there are, we can plug that value into our equation for N and solve for N.

N = 30 - D

N = 30 - 29

N = 1

Therefore, there are 29 dimes and 1 nickel.

Hope this helps!

5 0
3 years ago
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