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3 years ago

I neep help asap deadline 4:00pm

Mathematics

1 answer:

shutvik [7]3 years ago

5 0

Answer: B each charm costs 15 dollars

Step-by-step explanation: because each money increment is 15$ so the answer is $15

~Brainliest would be appreciated

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Find the value of q in the following system so that the solution to the system is(4,2) 3x-2y=8

Nataliya [291]

We have that
3x-2y=8 -----> equation 1
2x+3y=Q----> equation 2

the solution is the point (4,2)
in the equation 2 substitute the value of
x=4
y=2
so
2x+3y=Q------> 2*4+3*2=Q-------> Q=8+6------> Q=14

the answer is
Q=14

3 0

3 years ago

X-2(x+10)=12 , -15=5(3q-10)-5q Please Help

Rashid [163]

Answer:

-4,3.5

Step-by-step explanation:

1st one

x-2x-20 = 12

-x = 32

x=-4

2nd one

-15=15q-50 - 5q

35= 10q

q = 3.5

3 0

3 years ago

HELP FOR BRAINLIEST !!

julia-pushkina [17]

D is the answer because rise over run is going to left and plus 2 is on the y axis

5 0

3 years ago

How many 5-member chess teams can be chosen from 15 interested players? Consider only the members selected, not their board posi

ryzh [129]

Answer:

3003 number of 5-member chess teams can be chosen from 15 interested players.

Step-by-step explanation:

Given:

Number of the interested players = 15

To Find:

Number of 5-member chess teams that can be chosen = ?

Solution:

Combinations are a way to calculate the total outcomes of an event where order of the outcomes does not matter. To calculate combinations, we will use the formula $nCr = \frac{n!}{r!(n - r)!}$

where

n represents the total number of items,

r represents the number of items being chosen at a time.

Now we have n = 15 and r = 5

Substituting the values,

$15C_5 = \frac{15!}{5!(15- 5)!}$

$15C_5 = \frac{15!}{5!(10)!}$

$15C_5 = \frac{15\times \times 14 \times 13 \times 12 \times 11 \times 10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 }{5 \times 4 \times 3 \times 2 \times 1(10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1)}$

$15C_5 = \frac{15\times \times 14 \times 13 \times 12 \times 11}{(5 \times 4 \times 3 \times 2 \times 1)}$

$15C_5 = \frac{360360}{120}$

$15C_5 = 3003$

7 0

3 years ago

The coordinates of a point on a coordinate grid are (−3, 7). The point is reflected across the x-axis to obtain a new point. The

shepuryov [24]

The reflected points would be (-3,-7)

The x coordinate would stay the same but the y-coordinate would be the opposite

8 0

3 years ago