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hjlf
3 years ago
11

Williiam lost 25% of his marble,gave 1/6 of the remainder to his.Brother and had 120 marbles left.How many marbles did he have a

t first?
Mathematics
1 answer:
bija089 [108]3 years ago
5 0

Answer:

Number of marbles with Williams at the starting = 192

Step-by-step explanation:

Let total number of marbles with Williams = m

He lost marbles = 25% of the total number

                           = \frac{25}{100}\times m

                           = \frac{m}{4}

Remaining marbles with Williams = m - \frac{m}{4}

                                                        = \frac{3m}{4}

He gave marbles to his brother = \frac{1}{6}th of the remaining marbles

                                                    = \frac{1}{6}\times \frac{3m}{4}

                                                    = \frac{m}{8}

Remaining marbles after giving marbles to his brother = 120

Therefore, \frac{3m}{4}-\frac{m}{8}=120

\frac{6m}{8}-\frac{m}{8}=120

\frac{5m}{8}=120

m = \frac{120\times 8}{5}

m = 192

Number of marbles with Williams at the starting = 192

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