All categories

3 years ago

Find the median value. 1428, 961, 1258, 1324, 1185

1 answer:

7 0

Answer: 1258

Step by Step: Median simply means the middle value

rearrange the numbers from least to greatest

961, 1185, 1258, 1324, 1428

in this set, you can see that 1258 is the middle number

You might be interested in

I will mark as BRAINLIEST and 8 points if correct.

g100num [7]

Answer:

the answer is d

Step-by-step explanation:

6 0

3 years ago

Pls help!!! What is the annual interest for a principle of $5,500 at a simple interest rate of 4.5%?

Verdich [7]

Answer:

Hi Ok So I might be wrong but Here is my answer

$1237.50

r = 4.5% = 0.045

I = prt

I = 5500*0.045*5

= $1237.50

Hope i helped pls mark me as brain list if I'm correct

Step-by-step explanation:

3 0

3 years ago

A. ASA<br> B. CPCTC<br> C. AAS<br> D. SAS

Ede4ka [16]

Answer:

It is ASA congruence rule as the 2 angles and the included side of the triangle are equal

6 0

3 years ago

Read 2 more answers

Suppose quantity s is a length and quantity t is a time. Suppose the quantities v and a are defined by v = ds/dt and a = dv/dt.

finlep [7]

Answer:

a) $v = \frac{[L]}{[T]} = LT^{-1}$

b) $a = \frac{[L}{T}^{-1}]}{{T}}= L T^{-1} T^{-1}= L T^{-2}$

c) $\int v dt = s(t) = [L]=L$

d) $\int a dt = v(t) = [L][T]^{-1}=LT^{-1}$

e) $\frac{da}{dt}= \frac{[L][T]^{-2}}{T} = [L][T]^{-2} [T]^{-1} = LT^{-3}$

Step-by-step explanation:

Let define some notation:

[L]= represent longitude , [T] =represent time

And we have defined:

s(t) a position function

$v = \frac{ds}{dt}$

$a= \frac{dv}{dt}$

Part a

If we do the dimensional analysis for v we got:

$v = \frac{[L]}{[T]} = LT^{-1}$

Part b

For the acceleration we can use the result obtained from part a and we got:

$a = \frac{[L}{T}^{-1}]}{{T}}= L T^{-1} T^{-1}= L T^{-2}$

Part c

From definition if we do the integral of the velocity respect to t we got the position:

$\int v dt = s(t)$

And the dimensional analysis for the position is:

$\int v dt = s(t) = [L]=L$

Part d

The integral for the acceleration respect to the time is the velocity:

$\int a dt = v(t)$

And the dimensional analysis for the position is:

$\int a dt = v(t) = [L][T]^{-1}=LT^{-1}$

Part e

If we take the derivate respect to the acceleration and we want to find the dimensional analysis for this case we got:

$\frac{da}{dt}= \frac{[L][T]^{-2}}{T} = [L][T]^{-2} [T]^{-1} = LT^{-3}$

7 0

3 years ago

A solution is the value(s) of the variable that makes the algebraic sentence _____.

stiv31 [10]

The answer you are looking for is TRUE, the third option. The function of a solution is to prove that the values of the variables are true. Hope this is useful for you

5 0

3 years ago

Read 2 more answers