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Paladinen [302]
3 years ago
6

Write an equation of a line in slope intercept form to the given line and pass through the given point

Mathematics
2 answers:
ValentinkaMS [17]3 years ago
6 0
Okay so the equation given to you, tells you that the slope must be 4. The line must pass through the point (4,8). so, you have to put it into point-slope form in order to find your answer. the equation for point slope form is y-y1 =m(x-x1). in the equation, y1 and x1 are given in the point (4,8), so you point slope equation will be y-8=4(x-4). then you solve the equation. hope this helps! :)

Aloiza [94]3 years ago
6 0

Slope intercept form is:

y = mx + b

"m" is the slope, "b" is the y-intercept (when x = 0)


I'm assuming that the equation of a line is parallel to the given line.

When lines are parallel, they have the same slope.

The given line's slope is 4, so the parallel line's slope is also 4


y = mx + b

y = 4x + b


To find b, you plug in the point (4,8) into the equation.

y = 4x + b

8 = 4(4) + b

8 = 16 + b  Subtract 16 on both sides

-8 = b


Your equation is:

y = 4x - 8

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Pls send the answer ​
luda_lava [24]

Answer:

a = \dfrac{46}{17}

b = 0

Step-by-step explanation:

\dfrac{2\sqrt{5} + \sqrt{3}}{2\sqrt{5} - \sqrt{3}} + \dfrac{2\sqrt{5} - \sqrt{3}}{2\sqrt{5} + \sqrt{3}} =

= \dfrac{2\sqrt{5} + \sqrt{3}}{2\sqrt{5} - \sqrt{3}} \times \dfrac{2\sqrt{5} + \sqrt{3}}{2\sqrt{5} + \sqrt{3}} + \dfrac{2\sqrt{5} - \sqrt{3}}{2\sqrt{5} + \sqrt{3}} \times \dfrac{2\sqrt{5} - \sqrt{3}}{2\sqrt{5} - \sqrt{3}}

= \dfrac{23 + 4\sqrt{15}}{17} + \dfrac{23 - 4\sqrt{15}}{17}

= \dfrac{46}{17}

a = \dfrac{46}{17}

b = 0

4 0
2 years ago
What number should be added to 95 to get a sum of 73
agasfer [191]
95 + x = 73
95 + -22 = 73
x= -22
The answer is -22.
5 0
3 years ago
What is the value of the following expression?<br><br>(1/4)³​
lara [203]

Answer:

1/64

Step-by-step explanation:

Note that 1³ = 1 and that 4³ = 64.

                           1³            1

Thus, (1/4)³ = ------------ = -------

                           4³           64

4 0
3 years ago
Read 2 more answers
If a sum of several numbers is odd, then at least one of the numbers is itself odd.
labwork [276]

Answer with Step-by-step explanation:

We are given that if sum of several numbers is odd

We have to prove that at least one of the number is itself odd.

Suppose, we have three numbers

a=6 , b=7,d=8

Sum of numbers=6+7+8=21=Odd number

We know that sum of two odd numbers is always an even number.

Sum of an odd number and an even number is always an odd number.

If we take even odd numbers then sum is always an even number and sum of odd odd numbers then the sum is always an odd number.

7+5+3=15

7+3+9+5=24

Sum of even numbers is always an even number.

Hence, there are atleast one numebr is odd then the sum of several number is odd.

4 0
4 years ago
Directions: Calculate the percent increase or decrease between the starting and ending
Sveta_85 [38]

I'll do the first two to get you started

===============================================

Problem 1

A = 3 = starting value

B = 10 = ending value

C = percent change

C = [ (B - A)/A ] * 100%

C = [ (10-3)/3 ] * 100%

C = (7/3) * 100%

C = 2.3333333 * 100%

C = 233.33333%

C = 233.3%

The positive C value means we have a percent increase. If C was negative, then we'd have a percent decrease.

<h3>Answer: 233.3% increase</h3>

===============================================

Problem 2

A = 9 = start value

B = 20 = end value

C = percent change

C = [ (B - A)/A ] * 100%

C = [ (20-9)/9 ] * 100%

C = (11/9)*100%

C = 1.2222222222*100%

C = 122.22222222%

C = 122.2%

<h3>Answer: 122.2% increase</h3>
7 0
3 years ago
Read 2 more answers
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