Question

What is the equation of a line that is parallel to x−2y=−4 and passes through the point (0, 0)?

Answer 1

Answer:

The equation of a line that is parallel to x−2y=−4 and passes through the point (0, 0) will be:  $x-2y=0$

Step-by-step explanation:

Given the line

$x-2y=-4$

$x+4 = 2y$

$y=\left(\frac{1}{2}\right)x+2$

$m_1=\frac{1}{2}$

so, the slope of the line parallel to the given line would have

the same slope as  $\frac{1}{2}=m$, and passed through the point (0, 0).

Therefore, the equation of the required line is given by

$y = mx+b$

$y=\left(\frac{1}{2}\right)x+0$

$y=\left(\frac{1}{2}\right)x$

$2y=x$

$x-2y=0$

Therefore,  the equation of a line that is parallel to x−2y=−4 and passes through the point (0, 0) will be:  $x-2y=0$