1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Vitek1552 [10]
3 years ago
6

What dd command would you use to copy the contents of a partition named /dev/drive1 to another partition, called /dev/backup?

Computers and Technology
1 answer:
Advocard [28]3 years ago
4 0

Answer:

dd if=/dev/drive1 of=/dev/backup

Explanation:

Linux operating system is an open-source computer application readily available to system operators. The terminal is a platform in the operating system used to write scripts like bash and directly communicate with the system kernel.

There are two commands used in bash to copy files, the "cp" and "dd". The dd is mostly used to copy files from one storage or partition to another. The syntax of dd is;

dd if= (source partition/directory) of= (target partition/directory)

You might be interested in
An idea concerning what will happen in the future. (Crossword)
dangina [55]

Answer:

<h2>Expectation </h2>

Explanation:

Expectation is  an idea concerning what will happen in the future

7 0
3 years ago
Python code 100 Random Numbers (twice)
Leona [35]

import random

i = 1

while i <= 100:

   print("#"+str(i)+": "+str(random.randint(1,100)), end=", ")

   i+=1

print()

i = 1

while i <= 100:

   print("#"+str(i)+": "+str(random.uniform(1,100)), end=", ")

   i += 1

I hope this helps!

8 0
3 years ago
To make something ready for some activity is to ________it.
WINSTONCH [101]

Answer:

prepare (e.g. SQL prepared statements)

parse/convert (e.g. parse a string as an int/convert an array to string)

Explanation:

4 0
3 years ago
*hacked*
galben [10]

Hey Litz06,

Sorry that happened to you.

Try changing your password to something complicated so it’s more secure.

5 0
3 years ago
Declare a character variable letterStart. Write a statement to read a letter from the user into letterStart, followed by stateme
oee [108]
  1. Answer: import java.util.Scanner; public class CharTestt {     public static void main(String[] args) {     System.out.println("Please enter a character ");     Scanner input = new Scanner(System.in);     char letterStart = input.next().charAt(0);     char thenextChar = (char)(letterStart+1);     System.out.print(letterStart);     System.out.println(thenextChar); } } Explanation: Import Scanner Class Prompt user to enter a character Read and save user's input in a variable char letterStart = input.next().charAt(0); Knowing that the next character using ASCII is +1, create a new character variable and add 1 print the character entered and the new character all on same line without spaces
5 0
3 years ago
Other questions:
  • 3k means about 3 thousand bytes. how would you express two hundred million bytes?
    8·1 answer
  • Why does people that gets abused not report?
    5·1 answer
  • If you want to import text into a DTP application that was first created in a word processing program, what must you do?
    9·2 answers
  • Look up and list the number of a local taxi or car service in your community. Include the company name and telephone number.
    13·1 answer
  • A certain database has numerous tables, but they do not share any fields in common. this database will not be as powerful as oth
    15·2 answers
  • What is the difference between an electronic notebook and electronic flash cards?
    8·1 answer
  • Why laptop computer is called micro computer?​
    8·1 answer
  • Which branch of science helps avoid or minimize stress-related injuries at workplace?
    14·1 answer
  • Why might you use the More button in the Find and Replace dialog box?
    10·1 answer
  • Computer science student jones has been assigned a project on how to set up sniffer. What just he keep in mind as part of the pr
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!