What is the slope-intercept form is?

Simplify u^2+3u/u^2-9<br> A.u/u-3, =/ -3, and u=/3<br> B. u/u-3, u=/-3

VashaNatasha [74]

  The correct answer is: Answer choice: [A]:
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→  " $\frac{u}{u-3}$ " ; " { u $\neq$ ± 3 } " ;

  →  or, write as: " u / (u − 3) " ;  {" u ≠ 3 "}  AND: {" u ≠ -3 "} ;
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Explanation:
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We are asked to simplify:

   $\frac{(u^2+3u)}{(u^2-9)}$ ;

Note that the "numerator" —which is: "(u² + 3u)" — can be factored into:
  → " u(u + 3) " ;

And that the "denominator" —which is: "(u² − 9)" — can be factored into:
  → "(u − 3) (u + 3)" ;
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Let us rewrite as:
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→ $\frac{u(u+3)}{(u-3)(u+3)}$ ;

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→ We can simplify by "canceling out" BOTH the "(u + 3)" values; in BOTH the "numerator" AND the "denominator" ;  since:

" $\frac{(u+3)}{(u+3)} = 1$ " ;

→ And we have:
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→  " $\frac{u}{u-3}$ " ; that is: " u / (u − 3) " ; { u $\neq 3$ } .
and: { u $\neq-3$ } .

→ which is:  "Answer choice: [A] " .
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NOTE:  The "denominator" cannot equal "0" ; since one cannot "divide by "0" ;

and if the denominator is "(u − 3)" ; the denominator equals "0" when "u = -3" ; as such:

"u $\neq$ 3" ;

→ Note: To solve: "u + 3 = 0" ;

Subtract "3" from each side of the equation;

→ " u + 3 − 3 = 0 − 3 " ;

→ u = -3 (when the "denominator" equals "0") ;

→ As such: " u $\neq$ -3 " ;

Furthermore, consider the initial (unsimplified) given expression:

→   $\frac{(u^2+3u)}{(u^2-9)}$ ;

Note:  The denominator is: "(u²  − 9)" .

The "denominator" cannot be "0" ; because one cannot "divide" by "0" ;

As such, solve for values of "u" when the "denominator" equals "0" ; that is:
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→ " u² − 9 = 0 " ;

→ Add "9" to each side of the equation ;

→ u² − 9 + 9 = 0 + 9 ;

→ u² = 9 ;

Take the square root of each side of the equation;
to isolate "u" on one side of the equation; & to solve for ALL VALUES of "u" ;

→ √(u²) = √9 ;

→ | u | = 3 ;

→ " u = 3" ; AND; "u = -3 " ;

We already have: "u = -3" (a value at which the "denominator equals "0") ;

We now have "u = 3" ; as a value at which the "denominator equals "0");

→ As such: " u $\neq 3$ " ; "u $\neq$ -3 " ;

or, write as: " { u $\neq$ ± 3 } " .

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6 0

3 years ago

Pls help i don’t get it , ill mark brainlist

jonny [76]

Answer:I don't either

Step-by-step explanation:

4 0

3 years ago

The longest spin of a basketball on one finger is 255 minutes.about how many hours is that

lidiya [134]

The longest spin of a basketball on one finger is 255 minutes or 4.25 hours.

Step-by-step explanation:

the longest spin of a basketball on one finger is 255 minutes.

We need to find how many hours is that.

So, we need to convert 255 minutes into hours.

We know that,

60 minutes = 1 hour

Using Unitary method:

60 minutes = 1 hour

1 minute = 1/60 hour

255 minutes = 1/60 * 255 hour

255 minutes = 255/60 hour = 4.25 hour

255 minutes is 4.25 hour.

So, The longest spin of a basketball on one finger is 255 minutes or 4.25 hours.

Keywords: Convert Minutes to Hour

Learn more about Convert Minutes to Hour at:

#learnwithBrainly

4 0

3 years ago

Topic Test

Radda [10]

Answer:

A. 2468 sq. ft.

Step-by-step explanation:

I calculated it logically

7 0

3 years ago

Solved by substitution for <br>y=x-6<br>y=8x+1

GenaCL600 [577]

Here is your system of equations:

$\left \{ {{y=x-6} \atop {y=8x+1}} \right.$

When solving a system of equations, you can either eliminate or substitute, however, I will be substituting since that's what the question is asking.

In the first equation, if y is equal to x - 6, I can substitute it with the y in the second equation with 8x + 1.

Here is your new equation:

$x-6 = 8x+1$

Since you have variables on both sides, you have to cancel it on either side. In the equation on the left, the variable is x. To cancel it out, you have to do the opposite of it, which is -x, or negative x. That means you have to subtract x to both equations.

$x-6-x = 8x+1-x$

$-6=7x+1 \rightarrow 7x+1=-6$

Now you have one variable and two regular integers. You have to leave the variable x alone to find its value. Along with it is +1, or positive 1. To remove it, you have to do the opposite of it, which is -1 or subtract 1.

$7x+1-1=-6-1$