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4 years ago

How do you solve for b1 A=1/2h(b1+b2)

1 answer:

3 0

Since b1 stand for base 1 you should find the base and plug in the numbers there’s parentheses so you solve this first so you’d solve _+_=_ usually theres a line going straight with a number around it that’s gonna be your height and your other 2 are the bases

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Find the missing side

Firdavs [7]

$\huge\mathbb{\red A \pink{N}\purple{S} \blue{W} \orange{ER}}$

$\sin(55) = \frac{19}{x} \\ \frac{ \sqrt{3} }{2} = \frac{19}{x} \\ x = \frac{19 \times 2 \times \sqrt{3} }{3} \\ x = 21.9 = 22 \: \: \: cm$

8 0

3 years ago

Katerina runs 15 miles in 2.5 hours

shusha [124]

Answer:

We have that The average number of minutes it takes her to run 1 mile

From the Question we are told that

Katerina runs 15 miles in 2 1/2 hours

Average number of minutes it takes her to run 1 mile

Generally

Therefore

The average number of minutes it takes her to run 1 mile

In conclusion

The average number of minutes it takes her to run 1 mile

Step-by-step explanation:

3 0

3 years ago

Write 256 as a product of prime factors

Kipish [7]

256 -> 4 -> 2 & 2
-> 64 -> 8 & 8
8 -> 4 & 2
4 -> 2 & 2
8 -> 4 & 2
4 -> 2 & 2
(I hope this format makes sense) So you are left with 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 or $2^{8}$ . I hope this helps!

6 0

3 years ago

Describe the transformation in g (x) = (-5/8x) as it relates to the graph of the parent function.

rusak2 [61]

Answer:

reflection over x axis then horizontal stretch by factor of 8/5

Step-by-step explanation:

f(x)=x

h(x) = -f(x) ... reflection over x axis (x,y) -> (x,-y)

-f(x) -> g(x) = (-5/8x) ...0 < |5/8| <1 ... horizontal stretch (x,-y) -> (x / (5/8) , -y)

3 0

3 years ago

Consider the function f(x)=x2e4x. f(x) has two inflection points at x = C and x = D with C≤D where C is and D is Finally for eac

fredd [130]

Answer:

the inflection points are

$x = -0.85, -0.14$

So,

$C = -0.85 \\D = -0.14$

It is concave down at the intervals

$(-\infty , -0.85] \cup [-0.14,\infty)$

And it would be concave up at

$(-0.85 , -0.14)$

Step-by-step explanation:

Remember that to find inflection points you need to find where

$f''(x) = 0$

Since

$f(x) = x^2 e^{4x}$

Then using the product and the chain rule you have that

$f'(x) = 2e^{4x} x(2x+1)$

And then, using again the chain rule and the product rule you have that

$f''(x) = 2e^{4x} (8x^2 +8x+1)$

Therefore you have to solve the equation

$8x^2 +8x+1 = 0$

Using the quadratic equation you get that there are two solutions, so the inflection points are

$x = -0.85, -0.14$

So,

$C = -0.85 \\D = -0.14$

Now remember that a function is concave up if the derivative is greater than zero and concave down if the derivative is less than zero. Therefor you have to solve these inequalties

$8x^2 +8x+1 < 0 \\8x^2 +8x+1 \geq 0$

And you would get that is concave down at the intervals

$(-\infty , -0.85] \cup [-0.14,\infty)$

And it would be concave up at

$(-0.85 , -0.14)$

8 0

3 years ago