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3 years ago

Can anyone please please help me with this

Mathematics

2 answers:

Alex_Xolod [135]3 years ago

7 0

1.) First add how much Pax needs to make the recipe one time.

1.25+2.50+1=4.75

Then multiply by 3

4.75×3=14.25

Answer is D

2.) 1 3/8

Answer is B

svlad2 [7]3 years ago

6 0

Answer:

it should be 14.25

Step-by-step explanation:

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Setler [38]

Answer:

$\large{ \boxed{ \tt{ - 20a {z}^{2} - 2 {z}^{3} - 2 {a}^{3} + 11 {a}^{2} z }}}$

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2 years ago

Braydon is performing the four arithmetic operations on 14 and 2.

Studentka2010 [4]

Well, let's just solve all these darn operations!

<em>14 + 2 = 16
</em><em>14 - 2 = 12
</em><em>14 * 2 = 28
</em><em>14 / 2 = 7
</em>
<em />So, what do you think the answer is? =)

7 0

3 years ago

You need four pieces of string that are 2.25 feet long to make bracelet. you have 20 feet of string.

-Dominant- [34]

In the way you asked the question, the answer is already there but I am going to assume u are asking how many bracelets you can make which would then put the answer at almost 9 bracelets.

8 0

4 years ago

Jan'ai was asked to determine the minimum for a function with zeros located at –1 and 5, which also has a y-intercept of (0, –25

sergey [27]

The first error in Jan'ai's work in determining the considered function is given by: Option D: She incorrectly determined the x-coordinate of the vertex.

<h3>What are the coordinates of vertex for a quadratic function?</h3>

For a quadratic function of the form $y = ax^2 + bx + c$ , its vertex form is obtained as:

$y = ax^2 + bx + c\\y =a(x^2 + bx/a) + c\\y = a(x^2 + 2(b/2a)x + (b/2a)^2 -(b/2a)^2 )+ c\\y = a(x^2 + 2(b/2a)x + (b/2a)^2) -a \times (b/2a)^2 + c\\\\y = a(x+b/2a)^2 - a \times (b/2a)^2 + c$

For the form $y = a(x-h)^2 + k$ , the vertex has coordinates (h, k)

Thus, for the obtained equation $y = a(x+b/2a)^2 - a \times (b/2a)^2 + c$ , we get the coordinates of vertex as:

$h = -b/2a$ , $k = c - a\times(b/2a)^2$

Thus, the coordinates of vertex of $y = ax^2 + bx + c$ is:

$(h,k) = (-b/2a, c - a \times (b/2a)^2 )$

The missing steps of work of Jan'ai are:

Begin to write a function in factored form. $f(x) = a(x+1)(x-5)$
Substitute x = 0, y = f(x) = -25 to determine a. $-25 = a(0+1)(0-5)$
Simplify and solve to find a. $a=5$
Rewrite the function. $f(x) = 5(x+1)(x-5)$
Rewrite in standard form. $f(x) = 5x^2-20x-25$
Find the x-coordinate of the vertex. $x = -20/2(5) = -20/10; x = -2$
Find the y-coordinate of the vertex.

$y = 5x^2-20x-25$

$y = 5(-2)^2-20(-2)-25$

$y = 35$

so (-2,35) is the coordinate of the vertex, which denotes the minimum.

So, as we see, in the 5th step, Jan'ai had the quadratic function $f(x) = 5x^2-20x-25$ ,

Comparing this to $f(x) = ax^2 + bx + c$ , we get a = 5, b = -20, c = -25

The vertex's x-coordinate will be on -b/2a = -(-20)/ 2(5) = 20/10 = 2

But Jan'ai didn't putted that negative sign before b. in the 6th step.

Thus, the first error in Jan'ai's work in determining the considered function is given by: Option D: She incorrectly determined the x-coordinate of the vertex.

Learn more about the vertex form of a quadratic equation here:

brainly.com/question/9912128

6 0

3 years ago

I need help with 40 and 39!!!

vagabundo [1.1K]

39-A
When you multiply 8 times 2 its 16 and 40-16 is 24
40-D
less than is towards the negatives and for less than or greater than you use open circles

3 0

3 years ago

Read 2 more answers