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avanturin [10]
3 years ago
10

Can anyone please please help me with this

Mathematics
2 answers:
Alex_Xolod [135]3 years ago
7 0

1.) First add how much Pax needs to make the recipe one time.

1.25+2.50+1=4.75

Then multiply by 3

4.75×3=14.25

Answer is D

2.) 1 3/8

Answer is B

svlad2 [7]3 years ago
6 0

Answer:

it should be 14.25

Step-by-step explanation:

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The lines represented by the equations 12y – 8x = -72 and y = 2/3 x – 3
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Answer:

They are parallel

Step-by-step explanation:

Same slope but different y-intercept

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3 years ago
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A worker at a snack stand opened a new box of cups. On the first day, the worker used 30 cups from the box. On the second day, t
Solnce55 [7]

Answer:

<em>630 cups</em>

Step-by-step explanation:

<u>Percentages</u>

This problem is most easily solved backward, i.e., from the final data up to the beginning.

There was a new box of cups and the worker at a snack stand opened it. He first used 30 cups from the box and the second day he uses 15% of the remaining cups in the box, and we are told that represents 90 cups.

If 15% (0.15) equals 90 cups, then the number of cups before the second day was 90/0.15 = 600 cups.

On the first day, we used 30 cups, thus the original number of cups in the box was 600+30=630 cups

7 0
3 years ago
How many more marmosets are there than mandrills?
LekaFEV [45]

Answer:

3

Step-by-step explanation:

5 0
3 years ago
The following data gives the speeds (in mph), as measured by radar, of 10 cars traveling north on I-15. 76 72 80 68 76 74 71 78
____ [38]

Answer:

71.123 mph ≤ μ ≤ 77.277 mph

Step-by-step explanation:

Taking into account that the speed of all cars traveling on this highway have a normal distribution and we can only know the mean and the standard deviation of the sample, the confidence interval for the mean is calculated as:

m-t_{a/2,n-1}\frac{s}{\sqrt{n} } ≤ μ ≤ m+t_{a/2,n-1}\frac{s}{\sqrt{n} }

Where m is the mean of the sample, s is the standard deviation of the sample, n is the size of the sample, μ is the mean speed of all cars, and t_{a/2,n-1} is the number for t-student distribution where a/2 is the amount of area in one tail and n-1 are the degrees of freedom.

the mean and the standard deviation of the sample are equal to 74.2 and 5.3083 respectively, the size of the sample is 10, the distribution t- student has 9 degrees of freedom and the value of a is 10%.

So, if we replace m by 74.2, s by 5.3083, n by 10 and t_{0.05,9} by 1.8331, we get that the 90% confidence interval for the mean speed is:

74.2-(1.8331)\frac{5.3083}{\sqrt{10} } ≤ μ ≤ 74.2+(1.8331)\frac{5.3083}{\sqrt{10} }

74.2 - 3.077 ≤ μ ≤ 74.2 + 3.077

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8 0
3 years ago
HELP!! Am lost with this and is due pretty soon!
Afina-wow [57]

Answer:

∠FJG= 135

Step-by-step explanation:

∠FJG + ∠GJH = 168 so

(6x - 15) + (x + 8) = 168

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plug it in ∠FJG

6(25) - 15 = 135

4 0
3 years ago
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