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Zigmanuir [339]
2 years ago
12

Part 1 of 2

Mathematics
1 answer:
Romashka [77]2 years ago
6 0

Answer:

4x²+1 which is the answer

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How do you determine the domain of a function ?
Sunny_sXe [5.5K]

Answer:

Let y = f(x) be a function with an independent variable x and a dependent variable y.

If a function f provides a way to successfully produce a single value y using for that purpose a value for x then that

chosen x-value is said to belong to the domain of f. If there is a requirement that a y-value produced by a function

must be a real number, the following conditions are commonly checked:

1. Denominators cannot equal 0.

2. Radicands (expressions under a radical symbol) of even roots (square roots, etc)  

cannot have a negative value.

3. Logarithms can only be taken of positive values.

4. In word problems physical or other real-life restrictions might be imposed, e.g. time is  

nonnegative, number of items is a nonnegative integer, etc.

8 0
2 years ago
Read 2 more answers
Simplify the expression \[\frac{6}{\sqrt{36} + \sqrt{27}} + \frac{6}{\sqrt{27} + \sqrt{18}} + \frac{6}{\sqrt{18} + \sqrt{9}}.\]
Viktor [21]

Answer:

= 18 ( 3 + 2(\sqrt{3}  + \sqrt{2} ))

Step-by-step explanation:

6(\sqrt{36} +\sqrt{27}) + 6(\sqrt{27} +\sqrt{18}) + 6(\sqrt{18} + \sqrt{9} )\\= 6( {6} +\sqrt{9*3}) + 6( \sqrt{9*3}  +\sqrt{9*2}) + 6(\sqrt{9*2} + 3 )\\= 6( {6} +3\sqrt{3}) + 6(3\sqrt{3} +3\sqrt{2}) + 6(3\sqrt{2} + 3 )\\=36 + 18\sqrt{3} + 18\sqrt{3} + 18\sqrt{2}+ 18\sqrt{2} + 18\\= 36+18  +18( \sqrt{3}+ \sqrt{3} +\sqrt{2} + \sqrt{2})\\= 54 + 18 (2\sqrt{3} +2\sqrt{2})\\=54 + 36\sqrt{3}  + 36\sqrt{2}\\= 18 ( 3 + 2(\sqrt{3}  + \sqrt{2} ))

7 0
3 years ago
Which function has real zeros at x = –8 and x = 5?
Tcecarenko [31]

Answer:

option B is the answer . thank me later , you guys are lame

3 0
2 years ago
Which expression is equivalent to the given expression? Assume the denominator does not equal zero.
bulgar [2K]
D
For these type of problems download photo math
It’ll be faster than here with steps!
8 0
2 years ago
a) Everyone on the team talks until the entire team agrees on one decision. O b) Everyone on the team discusses options and then
insens350 [35]

Answer:

a) Everyone on the team talks until the entire team agrees on one decision.

Step-by-step explanation:

Option B consists of voting and not everyone would like the outcome. Option C is making an outsider the decision maker, which can't be helpful since he / she won't have as strong opinions as the team itself. Option D is just plain wrong as it defeats the purpose of team work and deciding as one team. So, I believe option A makes the most sense

8 0
2 years ago
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