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SashulF [63]
3 years ago
7

You earn $10.00hr. you invest $4,000.00 at an interest rate of 5% apr for a year. how much interest did that savings earn in a y

ear in terms of hours of work?
A.)100 hrs
b.)20hrs
c.)40hrs
d.)400 hrs.
Mathematics
2 answers:
gizmo_the_mogwai [7]3 years ago
8 0

Answer:

The correct option is b.

Step-by-step explanation:

It is given that you earn $10.00 per hr.

Principal amount = $4,000.00

Rate of interest = 5%

Time = 1 year

Formula for simple interest:

I=P\times r\times t

where, P is Principal, r is rate of interest and t is time in years.

Substitute P=4000, r=0.05 and t=1 in the above formula.

I=4000\times 0.05\times 1

I=200

The interest earn in a year is $200.

1 hr = $10.00

\frac{200}{10}=20

The interest earn in a year in terms of hours of work is 20 hrs.

Therefore the correct option is b.

Vedmedyk [2.9K]3 years ago
5 0
You are investing $2,000 fro 3 months and the APR is 4% so you will get one quarter of the APR for a year. For the year 4% interest is $2,00 x .04 or $80 for the year. # months is 1/4 of a year so divide $80 by 4 to get the interest fro 3 months which is 20 so the answer is B.
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i f N(-7,-1) is a point on the terminal side of ∅ in standard form, find the exact values of the trigonometric functions of ∅.
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Answer:

sin\ \varnothing = \frac{-1}{10}\sqrt 2

cos\ \varnothing = \frac{-7}{10}\sqrt 2

tan\ \varnothing = \frac{1}{7}

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sec\ \varnothing = \frac{-5}{7}\sqrt 2

csc\ \varnothing = -5\sqrt 2

Step-by-step explanation:

Given

N = (-7,-1) --- terminal side of \varnothing

Required

Determine the values of trigonometric functions of \varnothing.

For \varnothing, the trigonometry ratios are:

sin\ \varnothing = \frac{y}{r}       cos\ \varnothing = \frac{x}{r}       tan\ \varnothing = \frac{y}{x}

cot\ \varnothing = \frac{x}{y}       sec\ \varnothing = \frac{r}{x}       csc\ \varnothing = \frac{r}{y}

Where:

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r = \sqrt{50

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r = \sqrt{25} * \sqrt 2

r = 5 * \sqrt 2

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<u>Solving the trigonometry functions</u>

sin\ \varnothing = \frac{y}{r}

sin\ \varnothing = \frac{-1}{5\sqrt 2}

Rationalize:

sin\ \varnothing = \frac{-1}{5\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}

sin\ \varnothing = \frac{-\sqrt 2}{5*2}

sin\ \varnothing = \frac{-\sqrt 2}{10}

sin\ \varnothing = \frac{-1}{10}\sqrt 2

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cos\ \varnothing = \frac{-7}{5\sqrt 2}

Rationalize

cos\ \varnothing = \frac{-7}{5\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}

cos\ \varnothing = \frac{-7*\sqrt 2}{5*2}

cos\ \varnothing = \frac{-7\sqrt 2}{10}

cos\ \varnothing = \frac{-7}{10}\sqrt 2

tan\ \varnothing = \frac{y}{x}

tan\ \varnothing = \frac{-1}{-7}

tan\ \varnothing = \frac{1}{7}

cot\ \varnothing = \frac{x}{y}

cot\ \varnothing = \frac{-7}{-1}

cot\ \varnothing = 7

sec\ \varnothing = \frac{r}{x}

sec\ \varnothing = \frac{5\sqrt 2}{-7}

sec\ \varnothing = \frac{-5}{7}\sqrt 2

csc\ \varnothing = \frac{r}{y}

csc\ \varnothing = \frac{5\sqrt 2}{-1}

csc\ \varnothing = -5\sqrt 2

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