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ch4aika [34]
3 years ago
7

How would you find the vertices of an image of a figure was rotated 270 degrees clockwise? 15 POINTS! DESPERATE

Mathematics
2 answers:
PilotLPTM [1.2K]3 years ago
7 0

Rotating 90° (counterclockwise): (x, y) → (-y, x)

Rotating 180° (counterclockwise): (x, y) → (-x, -y)

Rotating 270° (counterclockwise): (x, y) → (y, -x)

The easiest way to explain this is:

1) Draw a point <em>(I am going to choose (2, 4), which is in Quadrant 1)</em>

2) Now, rotate your paper <em>or graphing board</em>  90°

3) Next, assume that your x-axis is horizontal and y-axis is vertical based on your rotation which means that the point has now moved to Quadrant 2. What is the new coordinate of the point? <em>(-4, 2)</em>

*****************************************************

Rotating another 90° again is a rotation of 180° from the original point

Rotating yet another 90° is a rotation of 270°.  <em>Not to confuse you, but 270° counterclockwise is the same as 90° clockwise.</em>

boyakko [2]3 years ago
5 0

Rotation Coordinate Notation About the Origin:

90–degree counterclockwise: (x, y) → (-y, x)

180–degree counterclockwise: (x, y) → (-x, -y)

270–degree counterclockwise: (x, y) → (y, -x)

Use this to help you..

Example -

The vertices of a triangle are

( 1 , 3 ) ( 3 , -4 ) , ( - 6 , -8 )

270 degrees , clockwise , rotated from origin ( x , y ) - ( y , -x )

The first vertice = ( 1 , 3 )

after rotation - ( 3 , - 1 )

The second vertice = ( 3 , -4 )

After rotation - ( -4 , -3 )

The third vertice = ( -6 , - 8 )

After rotation - ( -8 , 6 )

Hope my answer helps!

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Need help w this please
rusak2 [61]
Solved using proportions.

8 0
3 years ago
PLEASE HELP
max2010maxim [7]

Hello!


So, this is quite the complex question, and here are the following steps:


What is the quotient of \frac{6-3\sqrt[3]{6}}{\sqrt[3]{9}}?

\frac{(6 - 3\sqrt[3]{6})\sqrt[3]{9^{2}}}{9} (rationalize the denominator)

\frac{3(2 -\sqrt[3]{6})\sqrt[3]{9^{2}}}{9} (factor 3 from the expression)

\frac{(2-\sqrt[3]{6})\sqrt[3]{9^{2}}}{3} (reduce the fraction with 3)

\frac{2\sqrt[3]{9^{2}}-\sqrt[3]{9^{2}}}{3} (distributive property)

\frac{2\sqrt[3]{81}-\sqrt[3]{486}}{3} (simplify 3 · 9²)

\frac{6\sqrt[3]{3}-3\sqrt[3]{18}}{3} (simplify the radical)

\frac{3(2\sqrt[3]{3}-3\sqrt[3]{18})}{3} (factor 3 from the expression)

2\sqrt[3]{3}-\sqrt[3]{18} (reduce the fraction)


The answer, is simply, choice A, 2\sqrt[3]{3} -\sqrt[3]{18} ≈ 0.263758.

5 0
3 years ago
Mr. Abraham is 36 years old. His wife is 6 years younger than him and their son is 24 years old younger than his wife. What is t
sesenic [268]
Hi!
We know that Mr. Abraham’s wife is 6 years younger than him, which is 36-6, which means his wife is 30 years old.

We also know that Mr A’s son is 24 years younger than his wife, which is 30-24, which is 6.

As of right now, we now know that:
Mr. A is 36
Mr. A’s wife is 30
Mr. A’s son is 6

It’s asking for the ratio of Him:Wife:Son, so 36:30:6.

BUT, it’s asking for simplest form, so divide each of those numbers by 6.

Your answer is: 6:5:1
8 0
3 years ago
Mr. Atkinson manages playgrounds for the 8 elementary schools in the Franklin School District. This year, he wants to put new sa
astra-53 [7]

Answer: 5 bags of sand

Step-by-step explanation:

Given

There are 8 elementary schools

3 Tons of sand is needed

It is contained in a 50- Pound bag

1 ton is equivalent to 2000 Pound

No of 50- Pound bag required is

\Rightarrow n=\dfrac{2000}{50}\\\\\Rightarrow n=40

These 40 bags will be required in 8 schools. So, each school requires

\Rightarrow \dfrac{40}{8}=5\ \text{bag}

8 0
2 years ago
Read 2 more answers
- 5+x=-8 how do solve this equation ​
zloy xaker [14]

Add 5 to both sides to get x alone and you will have your answer which is x= -3

5 0
3 years ago
Read 2 more answers
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