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ch4aika [34]
3 years ago
7

How would you find the vertices of an image of a figure was rotated 270 degrees clockwise? 15 POINTS! DESPERATE

Mathematics
2 answers:
PilotLPTM [1.2K]3 years ago
7 0

Rotating 90° (counterclockwise): (x, y) → (-y, x)

Rotating 180° (counterclockwise): (x, y) → (-x, -y)

Rotating 270° (counterclockwise): (x, y) → (y, -x)

The easiest way to explain this is:

1) Draw a point <em>(I am going to choose (2, 4), which is in Quadrant 1)</em>

2) Now, rotate your paper <em>or graphing board</em>  90°

3) Next, assume that your x-axis is horizontal and y-axis is vertical based on your rotation which means that the point has now moved to Quadrant 2. What is the new coordinate of the point? <em>(-4, 2)</em>

*****************************************************

Rotating another 90° again is a rotation of 180° from the original point

Rotating yet another 90° is a rotation of 270°.  <em>Not to confuse you, but 270° counterclockwise is the same as 90° clockwise.</em>

boyakko [2]3 years ago
5 0

Rotation Coordinate Notation About the Origin:

90–degree counterclockwise: (x, y) → (-y, x)

180–degree counterclockwise: (x, y) → (-x, -y)

270–degree counterclockwise: (x, y) → (y, -x)

Use this to help you..

Example -

The vertices of a triangle are

( 1 , 3 ) ( 3 , -4 ) , ( - 6 , -8 )

270 degrees , clockwise , rotated from origin ( x , y ) - ( y , -x )

The first vertice = ( 1 , 3 )

after rotation - ( 3 , - 1 )

The second vertice = ( 3 , -4 )

After rotation - ( -4 , -3 )

The third vertice = ( -6 , - 8 )

After rotation - ( -8 , 6 )

Hope my answer helps!

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s344n2d4d5 [400]
Well, this problem is best solved by setting up a system of two linear equations.

A linear equation can be defined 
y=mx+b
where 
b=initial value (when x=0), and
m=rate of increase or decrease.

In the given example, the x-axis represents hour, and the y-axis, number of cells.

Chemical #1 
initial value = b = 12000 cells
rate = m = -4000 / hr
The equation is therefore 
y1=-4000x+12000......................(1)

Similarly, for chemical #2
initial value = b = 6000 cells
rate = m = -3000 / hr
The equation is therefore
y2=-3000x+6000 .......................(2)

The time the two will have an equal sized colony would represent the solution of the system of equations (1) and (2), i.e. when  y1=y2
which means
-4000x+12000 = -3000x+6000
transpose and solve for x
4000x-3000x = 12000-6000
1000x=6000
x=6 hours.

At 6 hours from the start, 
y=-4000x+12000 = -4000*6+12000 = -24000+12000 = -12000 cells

So the solution is x=6, y=-12000, or (6,-12000)

Physical interpretation
Since cells cannot have a negative number, the two are actually equal before six hours, when they are both zero.
Case 1: y=0 when x=3
Case 2: y=0 when x=2

Therefore, after three hours, both trials will have zero cells.

You have to judge whether to give the mathematical solution (x=6,y=-12000) or the physical interpretation (x=3, y=0) as the answer.


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