Original price = P = $12,698
Depreciation rate = r = 11% = 0.11
Time in years = t = 3
New price = A
The formula used will be:
Using the values, we get:
Thus, the worth of Suzuki after 3 years will be $8951.70
Step-by-step explanation:
<em>1st year</em>:
(1200 x 3.5 x 1) ÷ 100 = $42
<em>2nd year:</em>
(1242 x 3.5 x 1) ÷ 100= $43.47
<em>3rd year:</em>
(1285.47 x 3.5 x 1) ÷ 100= $44.99≈ $45
<em>4th year:</em>
(1330.47 x 3.5 x 1) ÷ 100= $46.56
Compound interest:
$(42 + 43.47 + 45 + 46.56)
=<u>$ 177.03</u>
110 yards 1 mile 3600 sec
-------------- * ----------------- * -------------- = 14 miles per hour (answer)
16 sec 1760 yards 1 hr
Answer:
ok so
Step-by-step explanation:
8x + 7 + 7x - 2=90=>
=> 15x+5= 90
=> 15x=90 - 5=>
=> 15x =85= x= 5.6666...
The formula is E= kQ/ d^2
k is 9x10^9
i changed 15 cm to 0.15 m
=> 9x10^9 x 12 OVER (0.15)^2
the answer is 4.8x10^12 N/C
but this is the electric field.
to find electric field STRENGTH, it’s E= F/q and you did not give a value for the force
