Question

Write the equation of the line that is parallel to the line -3x+2y=10 and goes through the point (4,7).

Answer 1

Answer:

y=-3/2x+13

Step-by-step explanation:

Convert to slope-intercept form (y=mx+b):

-3x+2y=10

-3x-10+2y=0

-3x-10=-2y

-3/2x-5=y

y=-3/2x-5

Parallel lines have the same slope, so the slope of the equation will be m₁=m₂ where -3/2=-3/2

Solving for b, the y-intercept, we get:

y=-3/2x+b (Equation so far)

7=-3/2(4)+b [Plugging in (4,7)]

7=-12/2+b

7=-6+b

13=b

Therefore, the equation of the line that is parallel to the line -3x+2y=10 and goes through the point (4,7) is y=-3/2x+13