Answer:
(6.08,170.54)
Explanation:
It goes 6 to the left and 1 up
Using Pythagorean theorem= 1/6=tan(angle)
Inverse tan 1/6= angle
= 9.46 degrees
180-9.46= 170.54 degrees is the angle
1^2+(-6)^2=h^2
1+36=h^2
h= square root of 37
h= 6.08
Hope you get it!
Answer:
Step-by-step explanation:
Let the rate at which the bacteria grow be represented by the exponential equation
P(t) = P0e^kt
P(t) is the population of the bacteria after time t
P0 is the initial population
k is the constant of variation
t is the time
If the initial Population is 160 bacteria's, them the equation becomes;
P(t) = 160e^kt
b) if After 5 hours there will be 800 bacteria, this means
at t = 5 p(t) = 800
Substitute and get k
800 = 160e^5k
800/160 = e^5k
5 = e^5k
Apply ln to both sides
Ln5 = lne^5k
ln5 = 5k
k = ln5/5
k = 0.3219
Next is to calculate the population after 7hrs i.e at t = 7
P(7) = 160e^0.3219(7)
P(7) = 160e^2.2532
P(7) = 160(9.5181)
P(7) = 1522.9
Hence the population after 7houra will be approximately 1523populations
c) To calculate the time it will take the population to reach 2790
When p(t) = 2790, t = ?
2790 = 160e^0.3219t
2790/160 = e^0.3219t
17.4375 = e^0.3219t
ln17.4375 = lne^0.3219t
2.8587 = 0.3219t
t = 2.8587/0.3219
t = 8.88 hrs
Hence it will take approximately 9hrs for the population to reach 2790
Well, let's see . . .
You said that (a) men can dig (c) holes in (b) hours.
So . . . It takes (a) men (b / c) hours to dig one hole.
And . . . It takes One man (a b / c) hours to dig one hole.
Now . . . There are (b) holes to be dug.
It would take one man (a b / c)·(b) = (a b² / c) hours to dig them all.
But if you had 'x' men, it would only take them (c) hours to do it.
So c = (a b² / c) / x
x c = (a b² / c)
x = a b² / c² men .
Now, I lost the big overview while I was doing that,
and just started following my nose through the fog.
So I have to admit that I'm not that confident in the answer.
But gosh durn it. That's the answer I got, and I'm stickin to it.
Rrarrup !
Answer:
6
Step-by-step explanation:
But i cant see the picturess
