What is the approximate solution of the equation x^2+12=0
1 answer:
Answer:
![x=-2i\sqrt{3} , 2i\sqrt{3}](https://tex.z-dn.net/?f=x%3D-2i%5Csqrt%7B3%7D%20%2C%202i%5Csqrt%7B3%7D)
Step-by-step explanation:
The equation is already set equal to zero, so that is a good start
We then need to get x by itself. To do so we need to subtract 12 from both sides to get x² = -12
Then we need to take the square root of both sides
which gives us ![x=-2i\sqrt{3} , 2i\sqrt{3}](https://tex.z-dn.net/?f=x%3D-2i%5Csqrt%7B3%7D%20%2C%202i%5Csqrt%7B3%7D)
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