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ale4655 [162]
3 years ago
6

△HKO∼△FGO Two right triangles. The first triangle is labeled triangle HKO. Angle H is the right angle. Side KO which is the hypo

tenuse has a length of 10 units. The other right triangle is labeled triangle FGO. In this triangle, angle F is the right angle and side GO is the hypotenuse with a length of 15 units. The triangles meet at angle O forming a vertical angle. Angles H and F are both right angles. Points H comma O comma and G are on the same line. Points F comma O comma and K are on the same line.
What is the ratio of the area of △HKO to the area of △FGO ? Express your answer as a fraction. Enter your answer in the box.
Mathematics
1 answer:
Leya [2.2K]3 years ago
5 0
<h2>the area is the 74 that is the answer </h2>
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Wilma works at a bird sanctuary and stores birdseed in plastic containers. She has 2 small containers that hold 8 pounds of bird
Amanda [17]

Answer:

 60 lbs left over

Step-by-step explanation:  Since the small containers hold 8 lbs each you multiply 8 by 2 since there are 2 containers. Same for the large, multiply 9 by 12 because each container holds 12 lbs and there is 9 containers. Then, you subtract 4 from that total because she already used 4 lbs.

x=(2*8)+(9*12)-4 Multiply

x=16+108-4 Simplify

x=120

So, before she fills the bird feeders she has 120 lbs of bird seed. There are 30 bird feeders and since they hold 2 lbs each you multiply 30 and 2. Then you subtract that from the 120 lbs because she is filling the bird feeders with that seed.

120- (30*2)

120-60= 60 lbs left over

3 0
3 years ago
What is the average rate of change on the interval from 3 to 9?
sammy [17]

Answer:

5

Step-by-step explanation:

3 0
3 years ago
How to isolate scalars from a matrix
I am Lyosha [343]
The technique of matrix isolation involves condensing the substance to be studied with a large excess of inert gas (usually argon or nitrogen) at low temperature to form a rigid solid (the matrix). The early development of matrix isolation spectroscopy was directed primarily to the study of unstable molecules and free radicals. The ability to stabilise reactive species by trapping them in a rigid cage, thus inhibiting intermolecular interaction, is an important feature of matrix isolation. The low temperatures (typically 4-20K) also prevent the occurrence of any process with an activation energy of more than a few kJ mol-1. Apart from the stabilisation of reactive species, matrix isolation affords a number of advantages over more conventional spectroscopic techniques. The isolation of monomelic solute molecules in an inert environment reduces intermolecular interactions, resulting in a sharpening of the solute absorption compared with other condensed phases. The effect is, of course, particularly dramatic for substances that engage in hydrogen bonding. Although the technique was developed to inhibit intermolecular interactions, it has also proved of great value in studying these interactions in molecular complexes formed in matrices at higher concentrations than those required for true isolation.
3 0
3 years ago
Ms.graves gave her class 12 minutes to read. Carrie read 5 1/2 pages in that time. At what rate, in oages per hour, did Carrie r
Mila [183]

Answer:

C

Step-by-step explanation:

5 1/2 pages in 12 minutes

There are 5 sets of 12 minutes in 1 hour

5 1/2 x 5 = 27 1/2

Therefore she would read 27 1/2 pages in 1 hour

Thats essentially how i did it - sorry if its not a very good explanation.

4 0
3 years ago
Combine like terms to create an equivalent expression. 2(1/5m - 2/5) + 3/5<br><br> ​
Alexus [3.1K]

Answer:

\dfrac{2}{5}m-\dfrac{1}{5}

Step-by-step explanation:

First, use the distributive property a\cdot (b-c)=a\cdot b-a\cdot c. Thus,

2\cdot \left(\dfrac{1}{5}m-\dfrac{2}{5}\right)=2\cdot \dfrac{1}{5}m-2\cdot \dfrac{2}{5}=\dfrac{2}{5}m-\dfrac{4}{5}.

Then given expression will take look

\dfrac{2}{5}m-\dfrac{4}{5}+\dfrac{3}{5}.

This expression consists of three terms, one term with m and two terms without m. Combine terms without m:

-\dfrac{4}{5}+\dfrac{3}{5}=-\dfrac{1}{5}.

Therefore, an equivalent expression is

\dfrac{2}{5}m-\dfrac{1}{5}.

5 0
3 years ago
Read 2 more answers
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