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ale4655 [162]
2 years ago
6

△HKO∼△FGO Two right triangles. The first triangle is labeled triangle HKO. Angle H is the right angle. Side KO which is the hypo

tenuse has a length of 10 units. The other right triangle is labeled triangle FGO. In this triangle, angle F is the right angle and side GO is the hypotenuse with a length of 15 units. The triangles meet at angle O forming a vertical angle. Angles H and F are both right angles. Points H comma O comma and G are on the same line. Points F comma O comma and K are on the same line.
What is the ratio of the area of △HKO to the area of △FGO ? Express your answer as a fraction. Enter your answer in the box.
Mathematics
1 answer:
Leya [2.2K]2 years ago
5 0
<h2>the area is the 74 that is the answer </h2>
You might be interested in
please help!!! the study conducted was 6 days long: there was 72mm of plant food and it decreased an equal amount each day.
Anuta_ua [19.1K]

Answer:

f(x) = 72 - 12x

Step-by-step explanation:

No. of days of study = 6

Amount of food to use for the 6 days = 72 mm

Given that equal amount of food was used each day, amount used per day = \frac{72}{6} = 12 mm

This would enable us derive a function for the amount of food remaining f(x), which can be expressed as a function of the number of days that have passed, (x).

Thus, we would have:

f(x) = 72 - 12x

Let's check if this equation expresses the relation of the function well.

At the end of day 1, if we used, 12mm, we would have 72 - 12 = 60mm of food remaining.

If we replace x in the equation we derived, we would get the same 60mm as the amount of food remaining.

If you try 2, 3, 4, 5 days, you'd get same thing.

At the end of the study, after the 6th day, the food would remain nothing.

Replace 6 for x in the relation function derived, you'd get a value of 0.

6 0
3 years ago
I toss an unfair coin 12 times. This coin is 65% likely to show up heads. Calculate the probability of the following.
mars1129 [50]

Answer:

a. 0.0368

b. 0.99992131

c. 0.2039

d. 0.0048

e. 0.6533

Step-by-step explanation:

Let the probability of obtaining a head be p = 65% = 13/20 = 0.65. The probability of not obtaining a head is q = 1 - p = 1 -13/20 = 7/20 = 0.35

Since this is a binomial probability, we use a binomial probability.

a. The probability of obtaining 11 heads is ¹²C₁₁p¹¹q¹ = 12 × (0.65)¹¹(0.35) = 0.0368

b. Probability of 2 or more heads P(x ≥ 2) is

P(x ≥ 2) = 1 - P(x ≤ 1)

Now P(x ≤ 1) = P(0) + P(1)

= ¹²C₀p⁰q¹² + ¹²C₁p¹q¹¹

= (0.65)⁰(0.35)¹² + 12(0.65)¹(0.35)¹¹

= 0.000003379 + 0.00007531

= 0.0007869

P(x ≥ 2) = 1 - P(x ≤ 1)

= 1 - 0.00007869

= 0.99992131

c. The probability of obtaining 7 heads is ¹²C₇p⁷q⁵ = 792(0.65)⁷(0.35)⁵ = 0.2039

d. The probability of obtaining 7 heads is ¹²C₉q⁹p³ = 220(0.65)³(0.35)⁹ = 0.0048

e. Probability of 8 heads or less P(x ≤ 8) = ¹²C₀p⁰q¹² + ¹²C₁p¹q¹¹ + ¹²C₂p²q¹⁰ + ¹²C₃p³q⁹ + ¹²C₄p⁴q⁸ + ¹²C₅p⁵q⁷ + ¹²C₆p⁶q⁶ + ¹²C₇p⁷q⁵ + ¹²C₈p⁸q⁴

= = ¹²C₀(0.65)⁰(0.35)¹² + ¹²C₁(0.65)¹(0.35)¹¹ + ¹²C₂(0.65)²(0.35)¹⁰ + ¹²C₃(0.65)³(0.35)⁹ + ¹²C₄(0.65)⁴(0.35)⁸ + ¹²C₅(0.65)⁵(0.35)⁷ + ¹²C₆(0.65)⁶(0.35)⁶ + ¹²C₇(0.65)⁷(0.35)⁵ + ¹²C₈(0.65)⁸(0.35)⁴

= 0.000003379 + 0.00007531 + 0.0007692 + 0.004762 + 0.01990 + 0.05912 + 0.1281 + 0.2039 + 0.2367

= 0.6533

3 0
3 years ago
Using the formula C = 2πr, how would i find the circumference of a circle with diameter of 28 inches. and i have to round the as
arlik [135]
Sorry, this took me a while to upload!

5 0
2 years ago
Given a point (-3, 6) and a line y= 2x − 8, what is the slope of the line?
Eddi Din [679]

The slope is 2.

Since the line "y = 2x − 8" follows slope-intercept form (y = mx + b), and the slope is always m, we know that the value of the slope is 2.

6 0
3 years ago
PLEASE ANSWER ASAP !!!!!
tester [92]

Answer:

Domain:

3,6,12,18

Range:

5,7,9,10

Not a function

Step-by-step explanation:

X= Domain

Y= Range

The input 6 is pared with both 5 and 10

7 0
2 years ago
Read 2 more answers
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