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ale4655 [162]
3 years ago
6

△HKO∼△FGO Two right triangles. The first triangle is labeled triangle HKO. Angle H is the right angle. Side KO which is the hypo

tenuse has a length of 10 units. The other right triangle is labeled triangle FGO. In this triangle, angle F is the right angle and side GO is the hypotenuse with a length of 15 units. The triangles meet at angle O forming a vertical angle. Angles H and F are both right angles. Points H comma O comma and G are on the same line. Points F comma O comma and K are on the same line.
What is the ratio of the area of △HKO to the area of △FGO ? Express your answer as a fraction. Enter your answer in the box.
Mathematics
1 answer:
Leya [2.2K]3 years ago
5 0
<h2>the area is the 74 that is the answer </h2>
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8 0
3 years ago
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frozen [14]
So the first thing to do is get two points. Lets start easy lets plug in 0 for x
y = 2(0) + 1 \\ y = 1
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  • plug in 0 for y and solve to get x-intercept                                                   0=-10x+50, x-intercept is 5

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3 years ago
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