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ale4655 [162]
2 years ago
6

△HKO∼△FGO Two right triangles. The first triangle is labeled triangle HKO. Angle H is the right angle. Side KO which is the hypo

tenuse has a length of 10 units. The other right triangle is labeled triangle FGO. In this triangle, angle F is the right angle and side GO is the hypotenuse with a length of 15 units. The triangles meet at angle O forming a vertical angle. Angles H and F are both right angles. Points H comma O comma and G are on the same line. Points F comma O comma and K are on the same line.
What is the ratio of the area of △HKO to the area of △FGO ? Express your answer as a fraction. Enter your answer in the box.
Mathematics
1 answer:
Leya [2.2K]2 years ago
5 0
<h2>the area is the 74 that is the answer </h2>
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The area of the sector (As) of a circle may be calculated by the formula,
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Find the x and y intercepts 5y + 3x = 15
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First, find the x-intercept.

The x-intercept will be at the point (x, 0) where x is any real number. If we substitute the x-coordinate and the y-coordinate for the x and y variables in the equation, we can solve for x.

5y + 3x = 15
5(0) + 3x = 15
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We found the x-intercept now find the y-intercept with the same process.

The y-intercept will be at the point (0, y) where y is any real number.

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2 years ago
Suppose that the store manager of a small rural pharmacy is doing a linear regression of daily sales of over-the-counter (OTC) d
Doss [256]

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3.83

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Sum of square (SS) :

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Mean of y = Σy / n

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Standard Error = √(Σ(y - ybar)² / df) / √SS

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Standard Error = 3.83

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2 years ago
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