Answer: AA similarity theorem.
Step-by-step explanation:
Given : AB ∥ DE
Prove: ΔACB ≈ ΔDCE
We are given AB ∥ DE. Because the lines are parallel and segment CB crosses both lines, we can consider segment CB a transversal of the parallel lines. Angles CED and CBA are corresponding angles of transversal CB and are therefore congruent, so ∠CED ≅ ∠CBA.
Also ∠C ≅ ∠C using the reflexive property.
Therefore by AA similarity theorem , ΔACB ≈ ΔDCE
- AA similarity theorem says that if in two triangles the two pairs of corresponding angles are congruent then the triangles are similar .
Nsjsjsjsjsksvv go off xdgsjggwu
Answer:
20
Step-by-step explanation:
Evaluate for y= −5
(−5)2+(2)(−5)+5
(−5)2+(2)(−5)+5
=20
240 is probably multiplied some other number if theres another number on there to multiply or divide by.
B because if the circle has a radius of x2 the 1/2 of that would be a+c bringing in c to become abc or a+b+c
