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Thepotemich [5.8K]
3 years ago
9

Choose the term so achieve the output shown.

Computers and Technology
1 answer:
Aneli [31]3 years ago
4 0

Answer:

sqrt

Explanation:

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The process of transaction can guarantee the reliability of business applications. Locking resources is widely used in distributed transaction management (e.g; two phase commit, 2PC) to keep the system consistent. The locking mechanism, however, potentially results in various deadlocks. In service oriented architecture, the deadlock problem becomes even worse because multiple transactions try to lock shared resources in the unexpectable way due to the more randomicity of transaction requests, which has not been solved by existing research results. In this paper, we investigate how to prevent local deadlocks, caused by the resource competition among multiple sub-transactions of a gl obal transaction, and global deadlocks from the competition among different global transactions. We propose a replication based approach to avoid the local deadlocks, and a timestamp based approach to significantly mitigate the global deadlocks. A general algorithm is designed for both local and global deadlock prevention. The experimental results demonstrate the effectiveness and efficiency of our deadlock prevention approach. Further, it is also proved that our approach provides higher system performance than traditional resource allocation schemes.

This is the required answer.

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Which elements are visible when a user opens a new PowerPoint presentation?
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Explanation:

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Create an array of doubles to contain 5 values Prompt the user to enter 5 values that will be stored in the array. These values
Gre4nikov [31]

Solution :

$\#$include $$  

$\#$include $$    

void parse$\_$name($char \ full[]$, char first$[],$ char last$[])$

{

// to_get_this_function_working_immediately, _irst

// stub_it_out_as_below._When_you_have_everything_else

// working,_come_back_and_really_parse_full_name

// this always sets first name to "Noah"

int i, j = 0;

for(i = 0; full[i] != ' '; i++)

  first[j++] = full[i];

first[j] = '\0';  

// this always sets last name to "Zark"

j = 0;

strcpy(last, full+i+1);

// replace the above calls with the actual logic to separate

// full into two distinct pieces

}

int main()

{

char full[40], first[20], last[20];

double hours[5];

// ask the user to enter full name

printf("What is your name? ");

gets(full);

// parse the full name into first and last

parse_name(full, first, last);

// load the hours

for(int i = 0; i < 5; i++)

{

   printf("Enter hours for day %d: ", i+1);

   scanf("%lf", &hours[i]);

}

// create the time card

FILE* fp = fopen("timecard.txt", "w");

fprintf(fp, "First Name: %s\n", first);

fprintf(fp, "Last Name: %s\n", last);

double sum = 0.0;

for(int i = 0; i < 5; i++)

{

   fprintf(fp, "Day %i: %.1lf\n", i+1, hours[i]);

   sum += hours[i];

}

fprintf(fp, "Total: %.1f\n", sum);    

printf("Timecard is ready. See timecard.txt\n");

return 0;

}

3 0
3 years ago
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