Answer:
Offset bits: 3-bits
Set number of cache: 12-bits
Tag bits: 7-bits
22-bit physical address
Explanation:
Since the system is 32K so,
=2⁵.2¹⁰
=2¹⁵
As we know that it is 8-way set associative so,
=2¹⁵/2³
=2¹⁵⁻³
=2¹²
2¹² are cache blocks
22-bit physical address
Off-set bits are 3 as they are calulated from 8-way set associative information.
Set number of cache : 12-bits
For tag-bits:
Add off-set bits and cache bits and subtract from the total bits of physical address.
=22 - (12+3)
=22 - 15
=7
for i in range(20, 51, 2):
print(i)
Answer:
Option C is the correct option to the following question
Explanation:
Because there are not any limits is required of sending data and packets between host A and host B by the routers and the router permit more than one paths between the hosts for the establishment of the connectivity st two distinct locations in the routing protocol. The router transmits the packets between the hosts that is produced by link-state protocol.
Answer:
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