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3 years ago

I need these answered by the end of TODAY!

Mathematics

2 answers:

PSYCHO15rus [73]3 years ago

6 0

Andre has more.

Hope this helps :))

Lina20 [59]3 years ago

3 0

Answer: Andre has more.

Step-by-step explanation: Thats because Andre has $120 and Elena has only $90 and $120 is obviously greater than $90 so thats ur answer your welcome if this helped! :>

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Identify the correct phrase to complete the statement.

shusha [124]

B!!

~have a great day

8 0

3 years ago

Read 2 more answers

PLEASE HELP ME!

algol13

Step-by-step explanation:

$1.\sum_{i=1}^{5}3i$

The simplest method is "brute force". Calculate each term and add them up.

∑ = 3(1) + 3(2) + 3(3) + 3(4) + 3(5)

∑ = 3 + 6 + 9 + 12 + 15

∑ = 45

$2.\sum_{k=1}^{4}(2k)^{2}$

∑ = (2×1)² + (2×2)² + (2×3)² + (2×4)²

∑ = 4 + 16 + 36 + 64

∑ = 120

$3.\sum_{k=3}^{6}(2k-10)$

∑ = (2×3−10) + (2×4−10) + (2×5−10) + (2×6−10)

∑ = -4 + -2 + 0 + 2

∑ = -4

4. 1 + 1/4 + 1/16 + 1/64 + 1/256

This is a geometric sequence where the first term is 1 and the common ratio is 1/4. The nth term is:

a = 1 (1/4)ⁿ⁻¹

So the series is:

$\sum_{j=1}^{7}(\frac{1}{4})^{j-1}$

5. -5 + -1 + 3 + 7 + 11

This is an arithmetic sequence where the first term is -5 and the common difference is 4. The nth term is:

a = -5 + 4(n−1)

a = -5 + 4n − 4

a = 4n − 9

So the series is:

$\sum_{j=1}^{5}(4j-9)$

5 0

3 years ago

Which postulate can be used to prove that and are congruent?

Bezzdna [24]

Answer:

SSS

Step-by-step explanation:

Here we are given that:

AB≅ED

CA≅CD

AC bisects BD, so that means we have

BC≅CD

This gives us all three sides congruent.

So we can say here SSS congruency fits the best.

6 0

3 years ago

Read 2 more answers

State the domain and range of the following function:

mojhsa [17]

Answer:

$Domain = \{-3,0,2,1,6,3\}$

$Range = \{4,6,-2,-3,-7,2\}$

Step-by-step explanation:

Given

$\{(- 3,4), (0,6), (2, - 2), (1, - 3), (6, - 7), (3, 2)\}$

Required

The domain and range

A function is represented as:

$Function = \{(x_1,y_1),(x_2,y_2),....(x_n,y_n)\}$

Where

$x \to$ domain

$y \to$ range

So, we have:

$Domain = \{-3,0,2,1,6,3\}$

$Range = \{4,6,-2,-3,-7,2\}$

7 0

3 years ago

Let A be a set of numbers.

LUCKY_DIMON [66]

Answer:

a. closed under addition and multiplication

b. not closed under addition but closed under multiplication.

c. not closed under addition and multiplication

d. closed under addition and multiplication

e. not closed under addition but closed under multiplication

Step-by-step explanation:

Let A be a set of all integers divisible by 5.

Let $x,y$ ∈A such that $x=5m\,,\,y=5n$

Find $x+y,xy$

$x+y=5m+5n=5(m+n)$

So, $x+y$ is divisible by 5.

$xy=(5m)(5n)=25mn=5(5mn)$

So,

$xy$ is divisible by 5.

Therefore, A is closed under addition and multiplication.

Let A = { 2n +1 | n ∈ Z}

Let $x,y$ ∈A such that $x=2m+1\,,\,y=2n+1$ where m, n ∈ Z.

Find $x+y,xy$

$x+y=2m+1+2n+1=2m+2n+2=2(m+n+1)$

So,

$x+y$ ∉ A

$xy=(2m+1)(2n+1)=4mn+2m+2n+1=2(2mn+m+n)+1$

So,

$xy$ ∈ A

Therefore, A is not closed under addition but A is closed under multiplication.

$Let A=\{2,5,8,11,14,...\}$

Let $x=2,y=5$ but $x+y=2+5=7$ ∉A

Also,

$xy=2(5)=10$ ∉A

Therefore, A is not closed under addition and multiplication.

Let A = { 17n: n∈Z}

Let $x,y$ ∈ A such that $x=17n,y=17m$

Find x + y and xy

$x+y=17n+17m=17(n+m)$

$xy=(17m)(17n)=289mn=17(17mn)$

So,

$x+y,xy$ ∈ A

Therefore, A is closed under addition and multiplication.

Let A be the set of nonzero real numbers.

Let $x,y$ ∈ A such that $x=-1,y=1$

Find x + y

$x+y=-1+1=0$

So,

$x+y$ ∈ A

Also, if x and y are two nonzero real numbers then xy is also a non-zero real number.

Therefore, A is not closed under addition but A is closed under multiplication.

4 0

3 years ago