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1 year ago

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There are 10000 people living in a certain city. Suppose that the rate of population growth in the city is proportional to the n

umber of inhabitants. Suppose that 10% of the original amount increase in 30 years, how much will the population in the city after 60 years?

1 answer:

hichkok12 [17]1 year ago

7 0

Answer:

.............30000.............

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A rectangular plot of land has an area of 9/10 square mile. The length is 3/2 miles. What is the width?

jek_recluse [69]

Answer:

$\frac{3}{5}$

Step-by-step explanation:

The question is simple. All we have to do is divide $\frac{9}{10}$ by $\frac{3}{2}$ . The answer to that is $\frac{3}{5}$ .

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2 years ago

Read 2 more answers

A roast turkey is taken from an oven when its temperature has reached 185 degrees F and is placed on a table in a room where the

Vedmedyk [2.9K]

(a) Using Newton's Law of Cooling, $\dfrac{dT}{dt} = k(T - T_s)$ , we have $\dfrac{dT}{dt} = k(T - 75)$ where T is temperature after T minutes.
Separate by dividing both sides by T - 75 to get $\dfrac{dT}{T - 75} = k dt$ . Integrate both sides to get $\ln|T - 75| = kt + C$ .

Since $T(0) = 185$ , we solve for C:
$|185 - 75| = k(0) + C\ \Rightarrow\ C = \ln 110$
So we get $\ln|T - 75| = kt + \ln 110$ . Use T(30) = 150 to solve for k:
$\ln| 150 - 75 | = 30k + \ln 110\ \Rightarrow\ \ln 75 - \ln 110= 30k \Rightarrow \\ k= \frac{1}{30}\ln (75/110) = \frac{1}{30}\ln(15/22)$

So

$\ln|T - 75| = kt + \ln 110 \Rightarrow |T - 75| = e^{kt + \ln110} \Rightarrow \\ \\
|T - 75| = 110e^{kt} \Rightarrow T - 75 = \pm110e^{(1/30)\ln(15/22)t} \Rightarrow \\
T = 75 \pm110e^{(1/30)\ln(15/22)t}$

But choose Positive because T > 75. Temp of turkey can't go under.

$T(t) = 75 + 110e^{(1/30)\ln(15/22)t} \\
T(45) = 75 + 110e^{(1/30)\ln(15/22)(45)} = 136.929 \approx 137{}^{\circ}F$

(b)

$T(t) = 75 + 110e^{(1/30)\ln(15/22)t} = 75 + 110(15/22)^{t/30} \\
100 = 75 + 110(15/22)^{t/30} \\
25 = 110(15/22)^{t/30} 
\frac{25}{110} = (15/22)^{t/30} \\
\ln(25/110) / ln(15/22) = t/30 \\
t = 30\ln(25/110) / ln(15/22) \approx 116\ \mathrm{min}$

Dogs of the AMS.

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2 years ago

Which values of x and y satisfy 2x − y = 7 and 3x − 2y = 5 simultaneously?

photoshop1234 [79]

To solve problems like this you can either graph or solve mathematically. To do the ladder we need to solve for one variable at a time. So lets cancel one variable out.
Multiply equation 1 by 2
This will give 4x-2y=14
Now we can get rid of y by subtracting 2 from 1
This will give x=9
Plug back in to either equation, i will use equation 2
3(9)-2y=5 simplify
-2y=-22 solve
Y=11

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2 years ago

Find the area of each shape. Show your reasoning.

Troyanec [42]

Answer:

Those areas are: A 1 = 12, A 2 = 19

Step-by-step explanation:

The area of shape 1 : it consists of 1 square + 4 right triangles

Area of the square: A = a², area of the triangle: A = 1/2 · a · h

A 1 = 2² + 4 · 1/2 · 2 · 2 = 4 + 8 = 12

The area of shape 2 : it consists of 2 isosceles triangles

A 2 = 1/2 · 2 · 4 + 1/2 · 6 · 5 = 4 + 15 = 19

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2 years ago

Help pls! Brainliest!

blagie [28]

Answer:

y =-3000x +12000

Step-by-step explanation:

answer is

1) 12000 is the constant therefore when the number of hours is 0 the tickets are 12000

2) the number of tickets (y) are reducing by 3000 for each hour(x). thus the coefficient of variable x should be -3000 (negative because it is reducing)

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2 years ago