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Elena L [17]
3 years ago
10

WILL GIVE BRAINLEST PLZZ HELP MEEEE

Mathematics
1 answer:
shusha [124]3 years ago
6 0

Answer:

3 :)

Step-by-step explanation:

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Write an equation that gives the overall equilibrium constant in terms of the equilibrium constants and . If you need to include
shutvik [7]

Answer:

The answer is "k=k_1k_{2}^2"

Step-by-step explanation:

For point 1:

4NHH_3 \ (g) +5O_2\ (g)  \leftrightharpoons  4NO\ (g) +6H_2O \ (g)..................k_1\\\\

For point 2:

2 \times(2\ NO\ (o)+O_2 \ (g)  \leftrightharpoons  2NO_2\ (g)) ..................K_2\\\\

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3 years ago
Select the best answer for the question.
hoa [83]

c is the correct answer

8 0
3 years ago
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All functions have a domain and a range.<br> True<br> False
Elza [17]

Answer:

True

Step-by-step explanation:

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6 0
3 years ago
The temperature in Lakeside was 21°C. The temperature in Salem was 9°C. How much warmer was the temperature in Lakeside than the
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3 years ago
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The two dot plots show the number of miles ran by 14 students at the beginning and at the end of the school year compare each me
Naddika [18.5K]

The two dot plots are missing, so i have attached it.

Answer:

The mean at the beginning of the school year was 9.5 miles and the mean at the end of the school year was 10.2 miles

Step-by-step explanation:

From the attached image, we are told to compare the means for each plot to the nearest tenth.

Mean = Σx/n

Now, from the image, total number of miles run by the 14 students at the beginning of the school year is;

(1 × 7) + (2 × 8) + (4 × 9) + (4 × 10) + (2 × 11) + (1 × 12) = 133

Mean of miles run at the beginning of the school year = 133/14 = 9.5 miles

Again, from the table, total miles run at the end of the school year = (2 × 8) + (2 × 9) + (4 × 10) + (3 × 11) + (3 × 12) = 143

Mean of miles run at the end of the school year = 143/14 = 10.2 miles

Thus;

The mean at the beginning of the school year was 9.5 miles and the mean at the end of the school year was 10.2 miles

5 0
3 years ago
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