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MariettaO [177]
3 years ago
11

Please help meee with my math i am so confused!!! Thank youuuu

Mathematics
2 answers:
Rudik [331]3 years ago
6 0

Answer:


Step-by-step explanation:

x decreases w/o bound, so x becomes a very large -ve no.

f(x)=5^(x-1) becomes 5^(large -ve no.) which will be almost zero


x increases w/o bound, so x becomes a very large +ve no.

f(x)=5^(x-1) becomes 5^(large +ve no.) which will keep increasing w/o bound


if u provide wat the choices are from ur Q in comments, i will pick the right one 4 u


kkurt [141]3 years ago
4 0

Answer:

As x→-∞  f(x) →0

  As x→∞  f(x) →∞

Step-by-step explanation:

f(x) = 5^(x-1)

as x approaches negative infinity

f(x) = 5^ - ∞

     1/ 5^∞

   1/ big number

    0

As x→-∞  f(x) →0

as x approaches  infinity

f(x) = 5^  ∞

     5^∞

    big number

    As x→∞  f(x) →∞

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------------------------------------------------------------
Define the two numbers
-----------------------------------------------------------
Let the first number be x.
Let the second number be y.

------------------------------------------------------------
Form equations and solve x and y
------------------------------------------------------------
x + 2y = 14 ------------------ (1)
2x + y = 31 ------------------ (2)

------------------------------------------------------------
Equation (1) x 2
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2x + 4y = 28  ---------------(1a)

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Equation (1a) - 2
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3y = 28 - 31
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