Answer:
Step-by-step explanation:
x decreases w/o bound, so x becomes a very large -ve no.
f(x)=5^(x-1) becomes 5^(large -ve no.) which will be almost zero
x increases w/o bound, so x becomes a very large +ve no.
f(x)=5^(x-1) becomes 5^(large +ve no.) which will keep increasing w/o bound
if u provide wat the choices are from ur Q in comments, i will pick the right one 4 u
