Please help meee with my math i am so confused!!! Thank youuuu
2 answers:
Answer:
Step-by-step explanation:
x decreases w/o bound, so x becomes a very large -ve no.
f(x)=5^(x-1) becomes 5^(large -ve no.) which will be almost zero
x increases w/o bound, so x becomes a very large +ve no.
f(x)=5^(x-1) becomes 5^(large +ve no.) which will keep increasing w/o bound
if u provide wat the choices are from ur Q in comments, i will pick the right one 4 u
Answer:
As x→-∞ f(x) →0
As x→∞ f(x) →∞
Step-by-step explanation:
f(x) = 5^(x-1)
as x approaches negative infinity
f(x) = 5^ - ∞
1/ 5^∞
1/ big number
0
As x→-∞ f(x) →0
as x approaches infinity
f(x) = 5^ ∞
5^∞
big number
As x→∞ f(x) →∞
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