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crimeas [40]
3 years ago
5

The mean weight of the domesticated house cat is 9.2 pounds with a standard deviation of 3.4 pounds. If a cat has a z-score of -

1.3 for its weight, how much does it weigh? Write your answer as a complete sentence.
Mathematics
1 answer:
ra1l [238]3 years ago
5 0

Answer:

4.78 pounds

Step-by-step explanation:

We solve the above question using z score formula

z = (x-μ)/σ, where

x is the raw score

μ is the population mean = 9.2 pound

σ is the population standard deviation = 3.4 pounds

z = 1.3

We are to find x

Hence,

-1.3 = x - 9.2/3.4

Cross Multiply

-1.3 × 3.4 = x - 9.2

-4.42 = x - 9.2

x = -4.42 + 9.2

x = 4.78 pounds.

Therefore the weight of the cat is 4.78 pounds

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Mark makes commission on his sales of software. If he sells up to $20,000 in one month his commission is 10% of the total. If he
blsea [12.9K]
The answer is C. $5,355

In order to find this amount you need to find how much he makes in each month individually. We'll start with month one where he sold $13,500 worth of software. Since that number is under $20,000 we know that he makes 10%. So to find his earnings, we simply multiply the told sold by the percentage. 

$13,500 * 10% = $1,350

Now we need to find the amount for month two. Since he sold $26,700, which is more than $20,000 we know that he gets the 15% of the amount sold. Similarly to last time, we'll multiply the two together. 

$26,700 * 15% = $4,005

Now you can combine the two of them to find the overall amount. 

$1,350 + $4,005 = $5,355
3 0
3 years ago
A sawdust pile has a base diameter of 35 feet when it’s height is 30 feet, find the volume of the pile when it is at 50 feet tal
ladessa [460]

Answer:

The volume of the sawdust pile is 16041.7 feet.

Step-by-step explanation:

The sawdust pile formed is in the form of a cone.

The volume of a cone is:

V=\frac{1}{3}\ \pi r^{2}\ h

The information provided is:

<em>r</em> = radius of the base = diameter ÷ 2 = (35 ÷ 2) feet

<em>h</em> = height = 50 feet

Compute the volume of the sawdust pile as follows:

V=\frac{1}{3}\ \pi r^{2}\ h

   =\frac{1}{3}\times \frac{22}{7}\times (\frac{35}{2})^{2}\times 50\\\\=16041.6667\\\\\approx 16041.7\ \text{feet}

Thus, the volume of the sawdust pile is 16041.7 feet.

7 0
3 years ago
In the previous problem, how does the angle of depression from the top of the taller building relate to the angle of elevation f
tia_tia [17]
The angles of elevation and depression are formed by the line of sight and the horizontal line. When the line of vision is above the horizontal line, the angle is of elevation, and if the line of sight is below the horizontal, the angle is of depression.

 The angle of depresion from the top of the taller building and the angle of elevation from the top of the shorter building are alternate interior angles. Then, if the angle of depression of the taller building is 15° the angle of elevation of the shorter building is 15° too. To understand this, you should see the diagram attached. 

 In the diagram you can notice that both angles, of elevation and depression, have the same value.

 Then, the answer is: The angle of depresion from the top of the taller building and the angle of elevation from the top of the shorter building are alternate interior angles.

3 0
3 years ago
Write the expression without using exponents (-2y)^4
JulsSmile [24]

Answer:

16yyyy

Step-by-step explanation:

Getting rid of exponents:

  • (-2y)^4 =
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5 0
3 years ago
Read 2 more answers
NEED HELP ASAP!!! The table shows the relationship between the number of bracelets made and the number of beads used:
Svetlanka [38]
Answer: 49
reason:
okay so basically to get to 3 to 5 you have to add 2. To get to 21 to 35 you need to add 14. To get to 5 to 7 you need to add 2, therefore adding 14 to 35. It's a pattern :)
5 0
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